Question

我有这张桌子

private static void ReadPropertiesRecursive<Tt>(Tt obj, Type type, List<string> prefixes)
{

    foreach (PropertyInfo property in type.GetProperties())
    {
        if (property.PropertyType.GetTypeInfo().IsClass && property.PropertyType != typeof(string))
        {
            prefixes.Add(property.Name);
            var val = property.GetValue(obj);
            if (val == null)
                val = Activator.CreateInstance(property.PropertyType);
            property.SetValue(obj, val);
            ReadPropertiesRecursive(val, property.PropertyType, prefixes);
            prefixes.Remove(property.Name);
        }
        else
        {
            var propertyFullName = prefixes != null && prefixes.Count > 0 ? $"{prefixes.Aggregate((i, j) => i + "." + j)}.{property.Name}" : property.Name;

            property.SetValue(obj, dic[propertyFullName]);

            Console.WriteLine(propertyFullName);
        }
    }
}

和其他像这样的表

Table1
 id  |  name  |
  1  |   a    |
  2  |   c    |

如何将这两个表排序为结果

a b c d

DONE READING THIS但它只会给我这个结果

a c b d

当我尝试这个时

Table2
 id  |  name  |
  1  |   b    |
  2  |   d    |

Answer 1

您可以尝试改为使用两个表中的UNION：

SELECT id, name
FROM Table1
UNION ALL
SELECT id, name
FROM Table2
ORDER BY name

如果要保留有关每条记录的原始来源的信息，可以为其添加一列：

SELECT id, name, 't1' AS source
FROM Table1
UNION ALL
SELECT id, name, 't2'
FROM Table2
ORDER BY name

<强>更新

如果Codeigniter不支持UNION开箱即用，您始终可以将上述查询放入字符串并以原生方式执行：

$sql = "SELECT id, name FROM Table1 UNION ALL SELECT id, name FROM Table2 ORDER BY name";
$this->db->query($sql);

Answer 2

SELECT *
INTO #TEMP_TBL
FROM Table1 AS t1 
JOIN Table2 AS t2 
ON t2.id = t1.id

SELECT *
FROM #TEMP_TBL
ORDER BY ID, NAME

DROP TABLE #TEMP_TBL

Answer 3

如果您想使用加入，请尝试以下查询

select * from (select x.* from table1 as x  left join table2 as y on x.id = y.id) as z order by z.name;

Answer 4

我们也可以使用它：

SELECT * FROM (
    SELECT id, NAME FROM Table1
    UNION ALL
    SELECT id, NAME FROM Table2) t ORDER BY name

在许多表上按ORDER BY SQL

4 个答案: