我有一个实体和流畅的映射,看起来像这样。
public class Client : EntityWithTypedId<long>
{
[Length(Max=50)]
public virtual string GivenName { get; set; }
public virtual IList<Address> Addresses { get; set; }
}
public class ClientMap : ClassMap<Client>
{
public ClientMap()
{
Schema("dbo");
Table("Client");
Id(x => x.Id, "ClientId").GeneratedBy.Identity();
Map(x => x.GivenName, "GivenName");
HasManyToMany(x => x.Addresses)
.FetchType.Join()
.Cascade.AllDeleteOrphan()
.Table("ClientAddress")
.ParentKeyColumn("ClientId")
.ChildKeyColumn("AddressId")
.AsBag();
}
}
然后我执行像这样的ICriteria查询
return Session.CreateCriteria<Client>()
.CreateAlias("Organisation", "o").SetFetchMode("o", FetchMode.Join)
.CreateAlias("Addresses", "a").SetFetchMode("a", FetchMode.Join)
.Add(expression)
.AddOrder(Order.Asc("Surname")).AddOrder(Order.Asc("GivenName"))
.SetResultTransformer(new DistinctRootEntityResultTransformer())
.SetMaxResults(pageSize)
.SetFirstResult(Pagination.FirstResult(pageIndex, pageSize))
.Future<Client>();
使用NHProf我可以看到它执行这样的查询,该查询应返回所有客户端详细信息和地址
SELECT top 20 this_.ClientId as ClientId5_2_,
this_.GivenName as GivenName5_2_,
addresses4_.ClientId as ClientId,
a2_.AddressId as AddressId,
a2_.AddressId as AddressId0_0_,
a2_.Street as Street0_0_,
a2_.Suburb as Suburb0_0_,
a2_.State as State0_0_,
a2_.Postcode as Postcode0_0_,
a2_.Country as Country0_0_,
a2_.AddressTypeId as AddressT7_0_0_,
a2_.OrganisationId as Organisa8_0_0_,
o1_.OrganisationId as Organisa1_11_1_,
o1_.Description as Descript2_11_1_,
o1_.Code as Code11_1_,
o1_.TimeZone as TimeZone11_1_
FROM dbo.Client this_
inner join ClientAddress addresses4_
on this_.ClientId = addresses4_.ClientId
inner join dbo.Address a2_
on addresses4_.AddressId = a2_.AddressId
inner join dbo.Organisation o1_
on this_.OrganisationId = o1_.OrganisationId
WHERE (o1_.Code = 'Demo' /* @p4 */
and (this_.Surname like '%' /* @p5 */
or (this_.HomePhone = '%' /* @p6 */
or this_.MobilePhone = '%' /* @p7 */)))
ORDER BY this_.Surname asc,
this_.GivenName asc
按预期返回所有记录
但是,如果我然后编写像
这样的代码foreach(var client in clients)
{
if (client.Addresses.Any())
{
Console.WriteLn(client.Addresses.First().Street);
}
}
我仍然遇到N + 1问题,它在每个地址上执行选择。我怎么能避免这个?
答案 0 :(得分:1)
我认为你误解了这里发生了什么......将不同的结果转换器与分页结合使用几乎总是不正确的。考虑一下,在上面的查询中,您只获得了交叉产品的前20行。我猜测列表末尾的几个客户没有填充他们的集合,导致你的N + 1问题。
如果您需要进行分页操作,请考虑在集合映射上使用batch-size
提示,以帮助最小化N + 1问题。
注意:如果您的典型用例是一次显示20个网页,请将batch-size
设置为此值。
答案 1 :(得分:1)
使用CreateAlias(collection)
时,SetFetchMode(collection)
无效。
要想更好地加载集合,请参阅http://ayende.com/Blog/archive/2010/01/16/eagerly-loading-entity-associations-efficiently-with-nhibernate.aspx