Question

这些就是我所拥有的：

名为lamanInformasi的数据库表，其字段名为isi。

这就是我想要的：

用户可以上传多个文档或图像文件，文件将存储到数据库中。文件名将保存到isi字段，文件本身将保存到名为propic的文件夹中。用户还可以在网站上显示他们想要的文件并下载。

这就是我所做的：

我使用bootstrap插件来输入文件。我用了这个source。我刚刚使用了js和css文件夹中的文件。这是我的代码：

<html lang="en">
<head>
    <meta charset="UTF-8"/>
    <link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css" rel="stylesheet">
    <link href="../css/fileinput.css" media="all" rel="stylesheet" type="text/css" />
    <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/4.7.0/css/font-awesome.min.css">

    <script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <script src="../js/fileinput.js" type="text/javascript"></script>
    <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js" type="text/javascript"></script>
</head>
<body>
    <div class="container kv-main">
        <div class="page-header">
        <h1>Upload Files</h1>
        </div>

        <form enctype="multipart/form-data">
            <div class="form-group">
                <input id="file-5" class="file" type="file" multiple data-preview-file-type="any" data-upload-url="#">
            </div>
        </form>
    </div>
</body>
<script>
        $("#file-5").fileinput({
            uploadUrl: "{{ url('lamanInformasi') }}",
            uploadAsync: false,
            previewFileIcon: '<i class="fa fa-file"></i>',
            allowedPreviewTypes: 'image',
            previewFileIconSettings: {
                'doc': '<i class="fa fa-file-word-o text-primary"></i>',
                'xls': '<i class="fa fa-file-excel-o text-success"></i>',
                'ppt': '<i class="fa fa-file-powerpoint-o text-danger"></i>',
                'jpg': '<i class="fa fa-file-photo-o text-warning"></i>',
                'pdf': '<i class="fa fa-file-pdf-o text-danger"></i>',
                'zip': '<i class="fa fa-file-archive-o text-muted"></i>',
                'htm': '<i class="fa fa-file-code-o text-info"></i>',
                'txt': '<i class="fa fa-file-text-o text-info"></i>',
                'mov': '<i class="fa fa-file-movie-o text-warning"></i>',
                'mp3': '<i class="fa fa-file-audio-o text-warning"></i>',
            },
            previewFileExtSettings: {
                'doc': function(ext) {
                    return ext.match(/(doc|docx)$/i);
                },
                'xls': function(ext) {
                    return ext.match(/(xls|xlsx)$/i);
                },
                'ppt': function(ext) {
                    return ext.match(/(ppt|pptx)$/i);
                },
                'zip': function(ext) {
                    return ext.match(/(zip|rar|tar|gzip|gz|7z)$/i);
                },
                'htm': function(ext) {
                    return ext.match(/(php|js|css|htm|html)$/i);
                },
                'txt': function(ext) {
                    return ext.match(/(txt|ini|md)$/i);
                },
                'mov': function(ext) {
                    return ext.match(/(avi|mpg|mkv|mov|mp4|3gp|webm|wmv)$/i);
                },
                'mp3': function(ext) {
                    return ext.match(/(mp3|wav)$/i);
                },
            }
        });
</script>

这是我的问题

如何将文件保存到数据库？如何在网站上显示文件？如何使文件可下载？感谢

Answer 1

您需要为文件输入字段指定一个名称，如

<form enctype="multipart/form-data">
        <div class="form-group">
            <input id="file-5" name="image" class="file" type="file" multiple data-preview-file-type="any" data-upload-url="#">
        </div>
</form>

然后在您的控制器方法中，您可以访问上传的文件并获取各种属性

**EDIT**
$destinationPath = storage_path().'/uploads/';
or
$destinationPath = public_path().'/uploads/';

//storage_path will give the fully qualified path to the storage folder
//public_path will give the fully qualified path to the public folder
//uploads - is the folder name where you want to store the user uploaded files, could be any name you prefer.
**EDIT end**

// Retrieving An Uploaded File
$file = Input::file('image');

// Determining If A File Was Uploaded
if (Input::hasFile('image'))
{
    //
}

// Determining If An Uploaded File Is Valid
if (Input::file('image')->isValid())
{
    //
}

// Moving An Uploaded File
Input::file('image')->move($destinationPath);
Input::file('image')->move($destinationPath, $fileName); //$filename is the name by which you want to store the file - change the name if required by by app.

// Getting Requested file path
$path = Input::file('image')->getRealPath();

// Getting Original name of the file
//**Edit** - gives the original filename as on uploading user's system. **Edit end**
$name = Input::file('image')->getClientOriginalName();

// Getting uploaded File extention
$extension = Input::file('image')->getClientOriginalExtension();

// Getting Size of the file
$size = Input::file('image')->getSize();

// Getting MIME Type of uploaded file
$mime = Input::file('image')->getMimeType();

然后，您可以通过与案例Model中的数据库表对应的lamanInformasi或使用查询构建器直接将查询构建器与原始查询一起存储在数据库中。

查看laravel文档：
Database - query builder
Eloquent - model approach

您可以使用Laravel's filesystem从文件夹中检索文件，并为用户准备列表视图，以查看可供下载的文件。

然后使用可以利用Laravel's Response Download为用户提供下载功能。

希望这有帮助。

Laravel - 将文件上传到数据库

1 个答案: