Question

C不是比较字符。我曾多次尝试并且总是遇到问题。

我的代码是

@echo off
title Audit Script

for /F %%i in (C:\testlist.txt) DO call :test %%i

goto :eof    <- This jumps to the end of the file

:test
....
....

输入

#include <stdio.h>
#include <string.h>


int main(){
    int palavra[16];
    int frase[201];
    gets(palavra);
    gets(frase);
    printf("%s\n",palavra);
    printf("%s\n",frase);
    int i;
    int palavrasNaFrase=0;
    int tamanhoPalavra=strlen(palavra);
    int tamanhoFrase=strlen(frase);
    printf("tamanho frase %d\n",tamanhoFrase);
    for(i=0; i<tamanhoFrase; i++){
        printf("i = %d\n",i);
        printf("caracter: %c\n",palavra[0]);
        printf("caracter: %c\n",frase[i]);
        if(frase[i] == palavra[0]){
            printf("C is not comparing characters\n");/*
            int j=i+1,k=1;
            int letrasIguais=1;
            int cont=1;
            while(cont<tamanhoPalavra){
                if(frase[j]==palavra[k]){
                    letrasIguais++;
                }
                j++;
                k++;
                cont++;
            }
            if(letrasIguais==tamanhoPalavra){
                palavrasNaFrase++;
            }*/
        }
    }
    //printf("%d\n",palavrasNaFrase);
    return(0);
}

out

ANA

ANAGOSTADEUMABANANA

进程返回0（0x0）执行时间：4.696 s 按任意键继续。

如此错误，我不知道该怎么做。请有人帮助我，如果有人能找到问题所在，为什么会这么做。有太多的错误和事情发生，不应该发生。我已经尝试和搜索了这么多次，总是我找到了比较字符串char的方法使用字符串[position] == string2 [position]是正确的但是在这个程序中没有用，我不知道为什么这么多的bug ！请有人帮帮我，给我一个灯！我究竟做错了什么？感谢

Answer 1

你正在定义这样的数组：

int palavra[16];
int frase[201];

虽然它保留了足够的空间，但是当你将char与char进行比较时会出现问题：你可能将int与int（multi-char到multi-char）进行比较，这可能是你想要的（并且你可能有关于指针类型的警告）你忽略了）：

if(frase[i] == palavra[0]){

您必须将声明更改为使用char而不是

char palavra[16];
char frase[201];

使用警告进行编译可以按预期进行此操作。修复警告也会修复你的代码（提取警告，冗余编辑出来）：

$ gcc -Wall toto.c
toto.c: In function 'main':
toto.c:8:10: warning: passing argument 1 of 'gets' from incompatible pointer type
     gets(palavra);
          ^
In file included from toto.c:1:0:
c:\gnatpro\7.4.2\x86_64-pc-mingw32\include\stdio.h:491:17: note: expected 'char *' but argument is of type 'int *'

          ^
In file included from toto.c:1:0:
c:\gnatpro\7.4.2\x86_64-pc-mingw32\include\stdio.h:491:17: note: expected 'char *' but argument is of type 'int *'
   char *__cdecl gets(char *_Buffer) __MINGW_ATTRIB_DEPRECATED_SEC_WARN;
                 ^
     ^
toto.c:11:5: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *'
 [-Wformat=]
     printf("%s\n",frase);
     ^
toto.c:14:31: warning: passing argument 1 of 'strlen' from incompatible pointer type
     int tamanhoPalavra=strlen(palavra);
                               ^

char比较错误输出并且在C中没有比较

1 个答案: