Question

我正在构建一个简单的任务规划器。这是来自TaskController.php文件的片段。如何将这3个查询（任务，未完成，已完成）组合起来使其工作？我应该使用DQL吗？

 /**
 * Lists all task entities.
 *
 * @Route("/", name="task_index")
 * @Method("GET")
 */
public function indexAction()
{

    $em = $this->getDoctrine()->getManager();

    $tasks = $em->getRepository('TaskBundle:Task')->findByUser($this->getUser());      // all tasks of a specific user

    $notcompleted = $em->getRepository('TaskBundle:Task')->findByCompleted(false); //tasks that are not completed

    $completed = $em->getRepository('TaskBundle:Task')->findByCompleted(true); // all completed tasks


    return $this->render('task/index.html.twig', array(
        'notcompleted' => $notcompleted,
        'completed' => $completed,
        'tasks' => $tasks,
    ));


}

Answer 1

您可以使用Doctrine的\Doctrine\Common\Collections\Collection::partition()分割任务：

$em = $this->getDoctrine()->getManager();
$tasks = $em->getRepository('TaskBundle:Task')->findByUser($this->getUser());

$collection = new ArrayCollection($tasks);

list($completed, $notcompleted) = $collection->partition(function ($key, Task $task) {
    return $task->isCompleted();
});

return $this->render('task/index.html.twig', array(
    'notcompleted' => $notcompleted,
    'completed' => $completed,
    'tasks' => $tasks,
));

Answer 2

最简单的解决方案可能是过滤控制器中的任务：

$em = $this->getDoctrine()->getManager();
$tasks = $em->getRepository('TaskBundle:Task')->findByUser($this->getUser());

$notcompleted = $completed = [];

foreach ($tasks as $task) {
    if ($task->isCompleted()) {
       $completed[] = $tasK;
    } else {
        $notcompleted[] = $task;
    }
}

return $this->render('task/index.html.twig', array(
        'notcompleted' => $notcompleted,
        'completed' => $completed,
        'tasks' => $tasks,
    ));

在此解决方案中，您只进行一次数据库查询，而不是三次查询。

Symfony2 Doctrine结合了三个查询

2 个答案: