您好,我的问题是我正在使用app更新数据到db。我的问题是当我向db发送新数据时,如果输入为空,它会用0覆盖表中的现有数据。只有我有一些值,在我的情况下,输入中的数字才能正确更新。
如何检查我不发送的空输入?
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$mysql_host = "localhost";
$mysql_username = "root";
$mysql_password = "";
$mysql_database = "medvedgrad";
// First we create the connection
$pdo = new PDO("mysql:host=".$mysql_host .";dbname=".$mysql_database .";charset=utf8", $mysql_username, $mysql_password);
$pdo->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$data = json_decode(file_get_contents("php://input"));
$zm = $data->zlatni_medvjed;
$ck = $data->crna_kraljica;
$gv = $data->gricka_vjestica;
$dk = $data->dva_klasa;
$fk = $data->fakin;
// Then we prepare, and execute the query
$stmt = $pdo->prepare("UPDATE `stanje_piva` SET `zlatni_medvjed`=`zlatni_medvjed`+:zm, `crna_kraljica`=`crna_kraljica`+:ck, `gricka_vjestica`=`gricka_vjestica`+:gv, `dva_klasa`=`dva_klasa`+:dk,`fakin`=`fakin`+:fk WHERE `id`=1");
$stmt->execute(array("zm" => $zm, "ck" => $ck, "gv" => $gv, "dk" => $dk, "fk" => $fk));
?>
答案 0 :(得分:0)
if(!empty($zm) && !empty($ck) && !empty($gv) && !empty($dk) && !empty($fk)) {
$stmt->execute(array("zm" => $zm, "ck" => $ck, "gv" => $gv, "dk" => $dk, "fk" => $fk));
}
答案 1 :(得分:0)
您需要一种方法只将非空值包含在数组中,并仅更新那些值。
$updateArray = array();
$sqlString = "Update `stanje_piva` SET ";
foreach(['zm' => $zm, 'ck' => $ck, 'gv' => $gv, 'dk' => $dk, 'fk' => $fk] as $key => $value){
// add to updateArray ONLY IF NOT EMPTY
if($value != ''){
// add key/value to updateArray
array_push($updateArray, $key => $value);
// append key/value to sql string
switch($key){
case 'zm':
$sqlString .= "`zlatni_medvjed`=`zlatni_medvjed`+:zm, ";
break;
case 'ck':
$sqlString .= "`crna_kraljica`=`crna_kraljica`+:ck, ";
break;
case 'gv':
$sqlString .= "`gricka_vjestica`=`gricka_vjestica`+:gv, ";
break;
case 'dk':
$sqlString .= "`dva_klasa`=`dva_klasa`+:dk, ";
break;
case 'fk':
$sqlString .= "`fakin`=`fakin`+:fk, ";
break;
}
}
}
// remove last ', ' from sqlQuery
$sqlQuery = substr($sqlQuery, 0, strlen($sqlQuery)-2);
// add Where clause
$sqlQuery .= " WHERE `id`=1";
// prepare
$stmt = $pdo->prepare($sqlQuery);
// execute
$stmt->execute($updateArray);
编辑:忘了准备stmt,补充说。