我想创建一个PHP脚本,用于从数据库备份我选择的表。从Stack Overflow我发现了这个:
<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlUserName = "root";
$mysqlPassword = "";
$mysqlHostName = "localhost";
$DbName = "test";
$backup_name = "mybackup.sql";
$tables = "msc_market";
//or add 5th parameter(array) of specific tables: array("mytable1","mytable2","mytable3") for multiple tables
Export_Database($mysqlHostName,$mysqlUserName,$mysqlPassword,$DbName, $tables=false, $backup_name=false );
function Export_Database($host,$user,$pass,$name, $tables=false, $backup_name=false )
{
$mysqli = new mysqli($host,$user,$pass,$name);
$mysqli->select_db($name);
$mysqli->query("SET NAMES 'utf8'");
$queryTables = $mysqli->query('SHOW TABLES');
while($row = $queryTables->fetch_row())
{
$target_tables[] = $row[0];
}
if($tables !== false)
{
$target_tables = array_intersect( $target_tables, $tables);
}
foreach($target_tables as $table)
{
$result = $mysqli->query('SELECT * FROM '.$table);
$fields_amount = $result->field_count;
$rows_num=$mysqli->affected_rows;
$res = $mysqli->query('SHOW CREATE TABLE '.$table);
$TableMLine = $res->fetch_row();
$content = (!isset($content) ? '' : $content) . "\n\n".$TableMLine[1].";\n\n";
for ($i = 0, $st_counter = 0; $i < $fields_amount; $i++, $st_counter=0)
{
while($row = $result->fetch_row())
{ //when started (and every after 100 command cycle):
if ($st_counter%100 == 0 || $st_counter == 0 )
{
$content .= "\nINSERT INTO ".$table." VALUES";
}
$content .= "\n(";
for($j=0; $j<$fields_amount; $j++)
{
$row[$j] = str_replace("\n","\\n", addslashes($row[$j]) );
if (isset($row[$j]))
{
$content .= '"'.$row[$j].'"' ;
}
else
{
$content .= '""';
}
if ($j<($fields_amount-1))
{
$content.= ',';
}
}
$content .=")";
//every after 100 command cycle [or at last line] ....p.s. but should be inserted 1 cycle eariler
if ( (($st_counter+1)%100==0 && $st_counter!=0) || $st_counter+1==$rows_num)
{
$content .= ";";
}
else
{
$content .= ",";
}
$st_counter=$st_counter+1;
}
} $content .="\n\n\n";
}
//$backup_name = $backup_name ? $backup_name : $name."___(".date('H-i-s')."_".date('d-m-Y').")__rand".rand(1,11111111).".sql";
$backup_name = $backup_name ? $backup_name : $name.".sql";
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename=\"".$backup_name."\"");
echo $content;
}
?>
现在,在此代码中,我更改 $ tables 值以选择单个表或更多表。对于多个表,我放置了一个包含表名的数组。但问题是每次我得到所有表的完整备份,即使我每次得到相同结果时都改变 $ tables 值。如何仅获取所选表的备份?请帮帮我。
答案 0 :(得分:0)
如图所示,Export_Database()中的第五个参数值在调用时被false值覆盖,您需要传递数据库表数组,因为array_intersect()只能从数组参数中过滤类似的值。修改后的代码......
Export
答案 1 :(得分:0)
您的问题是array_intersect
正在处理值,而不是键。由于这些是一维数组,因此您需要像这样交叉键:
$target_tables = array_values(array_intersect(array_keys($target_tables), array_keys($tables)));
<强>说明:强> 基本上,您首先将数组更改为键数组,然后将它们相交,然后将其转换回值。