Question

嘿伙计们当我通过ajax调用发送请求时，我试图发送我的个人访问令牌，但令牌没有传递给请求。继续看到API rate limit exceeded for 94.143.188.0. (But here's the good news: Authenticated requests get a higher rate limit.错误。我试过做beforeSend:但是没有用。我搞砸了某个地方，不知道在哪里。

由于

<div>
  <button id="getGithub">Github</button>
  <div id="gitResults"></div>
</div>

<div>
  <button id="getCodewars">Codewars</button>
  <div id="cwarsResults"></div>
</div>

var getGithub = document.getElementById('getGithub');
var getCodewars = document.getElementById('getCodewars');
var gitResults = document.getElementById('gitResults');
var cwarsResults = document.getElementById('cwarsResults');
var token =  'bea978891ecb5acbfdb7c7c5cf141dd8889b6249';

getGithub.onclick = function() {
  $.getJSON({
       method: "GET",
       headers: { username: token },
       url: "https://api.github.com/users/dantesolis",
       dataType: "jsonp",
       success: function( returnData ) {
      console.log('This is the returnData' + returnData);
      console.log(returnData.data);
      for (var props in returnData.data) {
        console.log(returnData.data[props]);
        gitResults.innerHTML = gitResults.innerHTML + returnData.data[props]
      }
     //gitResults.innerHTML = returnData.data.avatar_url;
        }
    })
}

Answer 1

好的，所以在阅读了更多帖子并搜索谷歌后，我发现如果我将我的令牌作为参数传递它就可以了。这是非常不优雅的，它只是绕过了我所拥有的问题。主要是不知道如何在ajax请求中正确设置标头，但对于那些寻找答案的人。我正在发布我的代码。如果有人有更好的解决方案，请添加它。

<div>
  <button id="getGithub">Github</button>
  <div id="gitResults"></div>
</div>

var getGithub = document.getElementById('getGithub');
var gitResults = document.getElementById('getGithub');


getGithub.onclick = function() {
  var root =  "https://api.github.com";
  var user =  '/users/dantesolis';
  var gitHubToken = 'my_cool_token';


  $.getJSON({
      method: "GET",

        url: root+user+"?&access_token="+gitHubToken,
        dataType: "json",
        success: function( response ) {
          console.log('This is the returnData' + response);   

          var link = document.createElement('a');
          var p1 = document.createElement('p');
          var p2 = document.createElement('p');

          link.href = response.html_url; 
          link.innerHTML = '@dantesolis';
          p1.innerHTML = response.followers;
          p2.innerHTML = response.following;
          gitResults.appendChild(link);
          gitResults.appendChild(p1);
          gitResults.appendChild(p2);
        }, /* End of success */
       error: function (xhr, status, errorThrown) {
         console.log('Error');
         console.log(xhr.status);
       }
    })
}

Github Basic oauth令牌未与ajax请求一起发送

1 个答案: