例如我有一个数组:
String[] Array1 =
{"15", "1", "D1", "Wine", "1", "0",
"15", "3", "D3", "Tap water", "2", "2",
"15", "1", "M1", "Fish", "3", "0",
"9", "5", "D4", "Coffee", "2", "2",
"9", "2", "P2", "Cake", "2", "1"
};
someList.addAll(Arrays.asList(Array1));
我想按照数字顺序对每种类似的ArrayList进行排序,根据每行中的第二个值,即1,3,1,5,2到1,1,2,3,5,同时保持其他变量在同一行完整。我不允许创建另一个类来按顺序存储这些变量。有谁知道我怎么能这样排序呢?
答案 0 :(得分:0)
您使用了错误的数据结构。数组用于包含相同类型信息的相同类型 的多个变量 。
我建议你创建一个类并创建一个包含该类对象的数组,如下所示:
<强> Drink.class 强>
class Drink{
private int a;
private int b;
private String c;
private String drinkName;
private int d;
private int e;
public Drink(int a,int b,String c,String drinkName,int d,int e){
this.a=a;
this.b=b;
this.c=c;
this.drinkName=drinkName;
this.d=d;
this.e=e;
}
// Getters and setters here
public String getDrinkName(){
return drinkName;
}
// .....
}
然后在你的主要班级:
class MainClass{
List<Drink> drinks;
public static void main(String[] args){
drinks = new ArrayList<>();
drinks.add(new Drink(15,1,"D1","Wine",1,0));
drinks.add(new Drink(15,3,"D3","Tap Water",2,2));
// Etc...
// You can retrieve elements using .get(index) and then use getters on it to retrieve informations
System.out.println(drinks.get(0).getDrinkName());
Collections.sort(drinks,new Comparator<Drink>(){
@Override
public int compare(Drink d1, Drink d2){
// Edit this method as you need
return d1.getA().compareTo(d2.getA());
}
});
}
}
答案 1 :(得分:0)
如果将所有元素作为String
值存储到array
,您将无法轻松对元素进行排序。相反,您可以使用OOP并定义名为MyCustomData
的自定义类型(类),然后将数据作为对象加载。
因此,您需要按照以下步骤操作:
(1)定义自定义类MyCustomData
(2)为MyCustomData
创建对象并将它们加载到数组中。
(3)现在,使用Comparator
您可以参考以下代码并注释:
MyCustomData类(正确命名此类):
public class MyCustomData {
private int value1;//holds your element to be sorted
//other values //define other values to hold fish, etc..
public int getValue1() {
return value1;
}
public void setValue1(int value1) {
this.value1 = value1;
}
}
对MyCustomData数组进行排序:
public static void main(String[] args) {
MyCustomData[] myCustomDataArray = new MyCustomData[5];
MyCustomData myCustomData1 = new MyCustomData();
myCustomData1.setValue1(1);
myCustomDataArray[0] = myCustomData1;
//Create and Load other objects myCustomDataArray[1] , [2], ....into array
Comparator<MyCustomData> comp = (MyCustomData data1, MyCustomData data2)
-> data1.getValue1()-data2.getValue1();
Arrays.stream(myCustomDataArray).sorted(comp);
}
答案 2 :(得分:0)
如果您创建一些有用的方法和比较器,您可以使用像bubble-sort这样的经典排序方法:
res/drawable/
更新:使用public static void main(String[] args) {
String[] array1 =
{"15", "1", "D1", "Wine", "1", "0",
"15", "3", "D3", "Tap water", "2", "2",
"15", "1", "M1", "Fish", "3", "0",
"9", "5", "D4", "Coffee", "2", "2",
"9", "2", "P2", "Cake", "2", "1"
};
Comparator<String[]> comparator = new Comparator<String[]>(){
@Override
public int compare(String[]a1, String[] a2) {
return Integer.valueOf(a1[1]).compareTo(Integer.valueOf(a2[1]));
}
};
int lineLength=6;
bubbleSort(array1,lineLength,comparator);
System.out.println(Arrays.toString(array1));
}
//classic bubble-sort algorithm
public static void bubbleSort(String[]array1,int lineLength,Comparator<String[]> comparator){
int numRow=array1.length/lineLength;
for(int i=0;i<numRow;i++){
for(int j=i+1;j<numRow;j++){
String[] extractArrayI = extractArray(array1, i, lineLength);
String[] extractArrayJ = extractArray(array1, j, lineLength);
if(comparator.compare(extractArrayI, extractArrayJ)>0){
swichLines(array1,i,j,lineLength);
}
}
}
}
//extract i-th row
public static String[] extractArray(String[]array,int i, int lineLength){
String [] a= new String[lineLength];
System.arraycopy(array, i*lineLength, a, 0, lineLength);
return a;
}
//Switch line i,j
public static void swichLines(String[]array,int i, int j,int lineLength){
String [] temp = new String[lineLength];
System.arraycopy(array, i*lineLength, temp, 0, lineLength);
System.arraycopy(array, j*lineLength, array, i*lineLength, lineLength);
System.arraycopy(temp, 0, array, j*lineLength, lineLength);
}
代替List<String>
:
String[]