我有一张这样的表
+----+------+
| ID | Name |
+----+------+
| 0 | Foo |
| 1 | Bar |
+----+------+
根据表格行,我想根据每一行计算排名,以便像
这样的查询SELECT *, [calculation] AS ranking
FROM table
ORDER BY ranking DESC
会返回类似
的内容+----+------+---------+
| ID | Name | Ranking |
+----+------+---------+
| 0 | Bar | 3 |
| 1 | Foo | 1 |
+----+------+---------+
我的问题是,我需要每行执行多个分配而不需要获取更多列;基本上像
@ranking:= 0
IF(Name LIKE $firstTerm, @ranking := @ranking + 1, @ranking := @ranking)
IF(Name LIKE $secondTerm, @ranking := @ranking + 1, @ranking := @ranking)
IF(Name LIKE $thirdTerm, @ranking := @ranking + 1, @ranking := @ranking)
对于每一行,最后我有0,1,2或3作为我表中每个条目的一个额外列
编辑:理论上是一个动态生成的查询,如
SELECT *
FROM table
ORDER BY SUM(
CASE
WHEN
(NAME LIKE $firstTerm AND NAME NOT LIKE $secondTerm AND NAME NOT LIKE $thirdTerm)
OR (NAME NOT LIKE $firstTerm AND NAME LIKE $secondTerm AND NAME NOT LIKE $thirdTerm)
OR (NAME NOT LIKE $firstTerm AND NAME NOT LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 1
WHEN (Name LIKE $firstTerm AND Name LIKE $secondTerm AND Name NOT LIKE $thirdTerm)
OR (Name NOT LIKE $firstTerm AND Name LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 2
WHEN (Name LIKE $firstTerm AND Name LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 3
ELSE 0
) DESC;
会按预期工作,但如果我们有超过3个术语,你可以想象这会发生什么变化!
答案 0 :(得分:2)
SELECT *,
IF(Name like $firstTerm, 1, 0) +
IF(Name like $secondTerm, 1, 0) as Ranking
FROM table ORDER BY Ranking DESC;
但是,如果数据集变大,计算复杂,使用搜索引擎(elasticsearch,solr)将更有效,更灵活。