Question

我知道这是使用位图的一个常见问题，但我不知道如何继续这个例子。特别是因为图像视图的大小不大，你会说它应该导致内存错误。我认为这是因为我经常创建位图而不是创建它，一旦蚂蚁每隔五秒显示一次，但不知道该怎么做。首先是创建位图的代码。

java class trapViews：

@Override
protected void onDraw(Canvas canvas) {
    super.onDraw(canvas);
    int x = 20;
    Random r = new Random();
    int i1 = r.nextInt(900 - 200) + 200;
    rnd = new Random();
    //Linke Seite

    System.gc();

    Bitmap image = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart);
    Bitmap resizedBitmap = Bitmap.createScaledBitmap(image, i1, 300, true);
        float left = (float) 0;
        float top = (float) (getHeight() - resizedBitmap.getHeight());
        canvas.drawBitmap(resizedBitmap, left, top, paint);

        //rechte Seite
        Bitmap images = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart1);
        Bitmap resizedBitmaps = Bitmap.createScaledBitmap(images, getWidth()-resizedBitmap.getWidth()-OwlHole, 300, true);
        float left1 = (float) (getWidth() - resizedBitmaps.getWidth());
        float top1 = (float) (getHeight() - resizedBitmaps.getHeight());
        canvas.drawBitmap(resizedBitmaps, left1, top1, paint);
    }
}

在屏幕的右侧和左侧以随机长度创建一个drawable。

现在我使用MainActivity

在Handler中每5秒调用一次

final Handler h = new Handler();
Runnable r = new Runnable() {
    public void run() {
        System.gc();
        traps();
        h.postDelayed(this,5000); // Handler neustarten
    }
}

private void traps() {
    container = (ViewGroup) findViewById(R.id.container);
    trapViews tv = new trapViews(this);
    container.addView(tv,
        ViewGroup.LayoutParams.MATCH_PARENT,
        ViewGroup.LayoutParams.MATCH_PARENT);
    //tV.setImageCount(8);
    h.postDelayed(r, 5000);
}

首先，它的工作方式就像我希望它能够工作一样。但每当一个新的抽签出现时，我的游戏就会滞后，并且在5-6次之后创建一个崩溃的

System.gc()和bitmap.recycle功能效果不佳。有人有解决方案吗？

Answer 1

请记住在替换位图后或当它不再可见时调用Bitmap.recycle（）。创建多个位图不是问题，而是在不使用循环来释放内存的情况下留下未使用的对象。

Answer 2

你每隔5秒创建一次位图，这不是一个好主意，因为它们总是一样的。你应该创建一次

 trapViews extends View{
    Bitmap image;
        Bitmap resizedBitmap;


        //rechte Seite
       Bitmap images ;
        Bitmap resizedBitmaps;

trapViews(Context c){
image = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart);
images = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart1);

}

@Override
protected void onDraw(Canvas canvas) {
        super.onDraw(canvas);
        int x = 20;
        Random r = new Random();
        int i1 = r.nextInt(900 - 200) + 200;
        rnd = new Random();
        //Linke Seite
          //I have left this bitmap in the here as it is affected by the random int
         resizedBitmap = Bitmap.createScaledBitmap(image, i1, 300, true);
            float left = (float) 0;
            float top = (float) (getHeight() - resizedBitmap.getHeight());
            canvas.drawBitmap(resizedBitmap, left, top, paint);

          //create this bitmap here as getWidth() will return 0 if created in the view's constructor
        if(resizedBitmaps == null)
         resizedBitmaps = Bitmap.createScaledBitmap(images, getWidth()-resizedBitmap.getWidth()-OwlHole, 300, true);
            float left1 = (float) (getWidth() - resizedBitmaps.getWidth());
            float top1 = (float) (getHeight() - resizedBitmaps.getHeight());
            canvas.drawBitmap(resizedBitmaps, left1, top1, paint);

}


}

OutOfMemory错误需要解决方案

2 个答案: