我正在尝试在Javascript中创建一个脚本,该脚本显示上次修改页面的时间,该脚本返回修改日期,时间,上午或下午格式。
显然我做错了什么。我无法让脚本运行,它将在我的函数AmPm中。有人可以帮忙吗?
// Javascript code for page modification
// Shows the date, time, am or pm, of modification.
// This section sets the date of modification
function lastModified() {
var modiDate = new Date(document.lastModified);
var showAs = modiDate.getDate() + "." + (modiDate.getMonth() + 1) + "." + modiDate.getFullYear();
return showAs
}
// This section sets the time of modification
function GetTime() {
var modiDate = new Date();
var Seconds
if (modiDate.getSeconds() < 10) {
Seconds = "0" + modiDate.getSeconds();
} else {
Seconds = modiDate.getSeconds();
}
// This section writes the above in the document
var modiDate = new Date();
var CurTime = modiDate.getHours() + ":" + modiDate.getMinutes() + ":" + Seconds
return CurTime
}
// This section decides if its am or pm
function AmPm() {
var hours = new Date().getHours();
var hours = (hours + 24 - 2) % 24;
var mid = 'AM';
if (hours == 0) { // At 00 hours (midnight) we need to display 12 am
hours = 12;
} else if (hours > 12) // At 12pm (Midday) we need to display 12 pm
{
hours = hours % 12;
mid = 'PM';
}
}
var mid = //This is where I am stuck!!
return AmPm
document.write("This webpage was last edited on: ");
document.write(lastModified() + " at " + GetTime() + AmPm());
document.write("");
document.write(" NZ Daylight Savings Time.");
document.write("");
答案 0 :(得分:0)
function formatAMPM(date) {
var hours = date.getHours();
var minutes = date.getMinutes();
var ampm = hours >= 12 ? 'pm' : 'am';
hours = hours % 12;
hours = hours ? hours : 12; // the hour '0' should be '12'
minutes = minutes < 10 ? '0'+minutes : minutes;
var strTime = hours + ':' + minutes + ' ' + ampm;
return strTime;
}