Question

我有可以从cli python脚本和Django view.py

导入的config.py

如何在config.py中了解 - 导入了哪个进程？ Django可能有一些特殊的变量吗？

我试过

public static void selectSpinnerItemByValue(Spinner spnr, long value) {
    SpinnerAdapter adapter = spnr.getAdapter();
    for (int position = 0; position < adapter.getCount(); position++) {
        if(adapter.getItemId(position) == value) {
            spnr.setSelection(position);
            return;
        }
    }
}

但似乎没有做我预期的事情。

我无法使用

if sys.stdin.isatty():
    ***

因为config.py被导入cli中的主文件。

对于Cli，我需要使用argparse解析命令行参数。在Django的情况下，我需要导入预定义的django-config.py

Answer 1

我认为最简单的方法是检查sys.argv。

import sys

# sys.argv[0] Should output your script name in a command line environment
# It should output wsgi.py if you're using wsgi, etc.

if sys.argv[0] == 'manage.py':
   print('called with manage.py, I\'m on the command line!')

elif sys.argv[0] == 'mod_wsgi':
   print('called with with ]mod_wsgi, I\'m run by an HTTP server!')

# In the case where you have something other than Apache with mod_wsgi running your server
# you'll need to manually determine the contents of sys.argv[0]
# elif sys.argv[0] == '<your-servers-response-here>':
#   print('called by your HTTP server!')

else:
   print('called with %s, I don\'t know where that is!' % sys.argv[0])

Answer 2

我会尝试背负django设置：

try:
    from django.conf import settings
    x = settings.DATABASES['default']['name'] == 'the name of your default database'
    from_django = True
except ImportError, AttributeError, KeyError:
    from_django = False

如何知道脚本是从django还是从cli运行的

2 个答案: