Question

我试图创建函数，它将8个值传递给使用QtDesigner制作的窗口应用程序中的进度条。也就是说有一个实际产生这个值的函数。我想每秒执行一次以获取theese值并更新显示值的进度条。

我结合了有关使用Python制作图形应用程序的教程，并制作了一个动态更新progess栏的应用程序：

Python Qt开发：https://www.youtube.com/watch?v=eD91nE8q8Nk
带线程的PyQt进度条：https://www.youtube.com/watch?v=ivcxZSHL7jM

问题是值正确传递，但是当发送信号时，整个应用程序崩溃并显示消息：

处理以退出代码139结束（由信号11中断： SIGSEGV）

这是我的代码：

生成值的模块（probkowanie.py）：

import time
from random import randint
import threading

def getSignals():
    time.sleep(1)
    signals = (randint(0, 100), randint(0, 100), randint(0, 100), randint(0, 100), randint(0, 100), randint(0, 100), randint(0, 100), randint(0, 100), )
    return signals

，这是主程序代码：

#!/usr/bin/env python
# -*- coding: utf-8 -*-

from PySide.QtCore import *
from PySide.QtGui import *
from PyQt4 import QtCore
import sys
import time

import signalPreview # window library
import probkowanie # values generating library

class MainDialog(QDialog, signalPreview.Ui_mainDialog):

    def __init__(self, parent=None):
        super(MainDialog, self).__init__(parent)
        self.setupUi(self)
        self.threadclass = ThreadClass()
        self.threadclass.start()
        self.connect(self.threadclass, QtCore.SIGNAL('MYO_SIGNALS'), self.updateProgressBars)

    def updateProgressBars(self, signals):
        self.progressBar.setValue(signals[0])

class ThreadClass(QtCore.QThread):
    def __init__(self, parent = None):
        super(ThreadClass, self).__init__(parent)

    def run(self):
        while 1:
            signals = probkowanie.getSignals()
            self.emit(QtCore.SIGNAL('MYO_SIGNALS'), 5) # this line causes crash
            print signals # it works correctly

app = QApplication(sys.argv)
form = MainDialog()
form.show()
app.exec_()

我认为这可能是由于混合库造成的。我使用PySide的QtCore，即使教程2是基于PyQt4。我的决定是因为1号教程是基于PySide的。我尝试过改变：

from PySide import QtCore

到

from PyQt4 import QtCore

然后我又收到了一堆错误，我不知道该怎么办：

Traceback (most recent call last):
   File "/usr/lib/pycharm/helpers/pydev/pydevd.py", line 1580, in <module>
        globals = debugger.run(setup['file'], None, None, is_module)
   File "/usr/lib/pycharm/helpers/pydev/pydevd.py", line 964, in run
        pydev_imports.execfile(file, globals, locals)  # execute the script
   File "/mnt/Grubas/Projekty/Biomed/MYO/myo.py", line 36, in <module>
        form = MainDialog()
   File "/mnt/Grubas/Projekty/Biomed/MYO/myo.py", line 20, in __init__
        self.connect(self.threadclass, QtCore.SIGNAL('MYO_SIGNALS'), self.updateProgressBars)
   TypeError: 'PySide.QtCore.QObject.connect' called with wrong argument types:
   PySide.QtCore.QObject.connect(ThreadClass, str, instancemethod)
   Supported signatures:
   PySide.QtCore.QObject.connect(PySide.QtCore.QObject, str, callable, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)
   PySide.QtCore.QObject.connect(PySide.QtCore.QObject, PySide.QtCore.QMetaMethod, PySide.QtCore.QObject, PySide.QtCore.QMetaMethod, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)
   PySide.QtCore.QObject.connect(PySide.QtCore.QObject, str, PySide.QtCore.QObject, str, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)
   PySide.QtCore.QObject.connect(PySide.QtCore.QObject, str, str, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)   PySide.QtCore.QObject.connect(str, callable, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)
   PySide.QtCore.QObject.connect(str, PySide.QtCore.QObject, str, PySide.QtCore.Qt.ConnectionType = Qt.AutoConnection)

@EDIT 在提供由@ekhumoro脚本提出的更改后，doens崩溃了，但现在我又收到了另一个错误：

QObject :: connect：无法对类型＆＃39; object＆＃39;的参数进行排队（确保＆＃39;对象＆＃39;使用qRegisterMetaType（）注册。）

我试图自己寻找解决方案，但我找不到我需要的确切代码。我也试过将信号类型从（对象）转换为（元组）或（列表），但它会导致另一个错误：

TypeError：用于调用元函数的未知类型（可能是信号）：元组

我发现的大多数解决方案都基于PyQT。是否有一种简单的方法可以为PySide重写它？这是一个解决方案的例子，它似乎是正确的，但使用PyQT： https://stackoverflow.com/a/2595607/2550466

Answer 1

你认为混合PySide和PyQt会导致问题是正确的，所以你需要删除其中一个。但是，崩溃本身可能是由PySide中的一个错误引起的。这里有一个类似问题的SO问题：

How to send None with Signals across threads?

因此，您还需要更改定义和发出MYO_SIGNALS的方式。

以下是您脚本的固定版本（已更改的行已注释）：

# from PySide.QtCore import *
# from PySide.QtGui import *
# from PyQt4 import QtCore
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys
import time

import signalPreview # window library
import probkowanie # values generating library

class MainDialog(QDialog):

    def __init__(self, parent=None):
        super(MainDialog, self).__init__(parent)
        self.setupUi(self)
        self.threadclass = ThreadClass()
        self.threadclass.start()
        # self.connect(self.threadclass, QtCore.SIGNAL('MYO_SIGNALS'), self.updateProgressBars)
        self.connect(self.threadclass, SIGNAL('MYO_SIGNALS'), self.updateProgressBars)

    def updateProgressBars(self, signals):
        self.progressBar.setValue(signals[0])

# class ThreadClass(QtCore.QThread):
class ThreadClass(QThread):
    def __init__(self, parent = None):
        super(ThreadClass, self).__init__(parent)

    def run(self):
        while 1:
            signals = probkowanie.getSignals()
            # self.emit(QtCore.SIGNAL('MYO_SIGNALS'), 5) # this line causes crash
            self.emit(SIGNAL('MYO_SIGNALS'), signals)
            print signals # it works correctly

app = QApplication(sys.argv)
form = MainDialog()
form.show()
app.exec_()

在Python中发出的信号导致退出代码139

1 个答案: