Question

我在SQL中有两个表，我需要能够根据表B中的时间戳进行连接，该时间戳早于或等于表A中的时间戳。

所以，这里有两个表的假数据和所需的输出：

已结案例（表A）

| id | resolution |         timestamp          |
------------------------------------------------
|  1 |     solved | 2006-10-05 11:55:44.888153 |
|  2 |     closed | 2007-10-07 12:34:17.033498 |
|  3 |    trashed | 2008-10-09 08:19:36.983747 |
|  4 |     solved | 2010-10-13 04:28:14.348753 |

分类（表B）


| id |    value    |         timestamp          |
-------------------------------------------------
|  1 |    freshman | 2006-01-01 12:02:44.888153 |
|  2 |   sophomore | 2007-01-01 12:01:19.984333 |
|  3 |      junior | 2008-01-01 12:02:28.746149 |

期望的结果

| id | resolution |         timestamp          |    value    |
--------------------------------------------------------------
|  1 |     solved | 2006-10-05 11:55:44.888153 |    freshman |
|  2 |     closed | 2007-10-07 12:34:17.033498 |   sophomore |
|  3 |    trashed | 2008-10-09 08:19:36.983747 |      junior |
|  4 |     solved | 2010-10-13 04:28:14.348753 |      junior |

所以，我知道代码需要如下所示，我只是无法弄清楚如何处理ON的{{1}}部分（$ 1和$ 2是将成为的变量传入）：

JOIN

我知道我可以使用一个子选择，但这将至少运行几千行，可能更多，我需要它真的很快;所以我希望有一个简单的条款可以做到。

Answer 1

如果您可以对表结构进行更改，我建议您更改分类表以包括结束日期和开始日期 - 以这种方式加入表格会更容易。

如果没有，我建议如下：

SELECT case.id, case.resolution, case.timestamp, class.value
  FROM closed_cases AS case
  LEFT JOIN (select c.*, 
                    (select min(timestamp)
                     from classifications c1
                      where c1.timestamp > c.timestamp) timeend
             from classifications c) AS class 
  ON case.timestamp >= class.timestamp and 
     (case.timestamp < class.timeend or class.timeend IS NULL)
  WHERE case.timestamp BETWEEN $1 AND $2;

编辑 - 结束日期分类：

SELECT case.id, case.resolution, case.timestamp, class.value
  FROM closed_cases AS case
  LEFT JOIN classifications AS class 
  ON case.timestamp >= class.timestamp and case.timestamp < class.timeend
  WHERE case.timestamp BETWEEN $1 AND $2;

Answer 2

更改时间戳并使用int作为连接表的键。这比比较日期

要快得多表1 FIELD1 域2 字段3 ConnectorField

表2 FIELD1 域2 字段3 ConnectorField

你需要做的就是 select * from table1 T1 inner join table2 T2 on T1.ConnectorField = T2.ConnectorField

Answer 3

如果你的 SQL 有窗口函数，那么可能是 8 及更高版本，最简单的方法是在分类时间戳上使用 LEAD function，有效地实现更简单的@user359040 的解决方案

Answer 4

SELECT case.id, case.resolution, case.timestamp, class.value
  FROM closed_cases AS case
  LEFT JOIN classifications AS class 
  ON case.timestamp >= class.timestamp
  WHERE case.timestamp BETWEEN $1 AND $2;

基于最近时间戳加入两个表的SQL查询

4 个答案: