Question

app.factory('WeatherApi', function($http) {
   var obj = {};

   obj.getLoc = function() {
      return $http.jsonp("http://ipinfo.io/json?callback=JSON_CALLBACK");
   };

   obj.getCurrent = function(city) {
      var api = "http://api.openweathermap.org/data/2.5/weather?q=";
      var units = "&units=metric";
      var appid = "&APPID=061f24cf3cde2f60644a8240302983f2"
      var cb = "&callback=JSON_CALLBACK";

      return $http.jsonp(api + city + units+ appid + cb);
   };
   return obj
});

有人可以解释这段代码的作用吗？我不明白所有不同的变量是什么。 obj.getLoc究竟做了什么？这是否意味着它创造了一个功能。那么它们最后是否构成一个链接然后json搜索被拉出的网页的数据？

Answer 1

此代码块定义了一个可在应用程序内重用的服务。

示例用法：

＆＃13;

var app = angular.module('app', []);

app.factory('WeatherApi', function($http) {
  var obj = {};

  obj.getLoc = function() {
    return $http.jsonp("http://ipinfo.io/json?callback=JSON_CALLBACK");
  };

  obj.getCurrent = function(city) {
    var api = "http://api.openweathermap.org/data/2.5/weather?q=";
    var units = "&units=metric";
    var appid = "&APPID=061f24cf3cde2f60644a8240302983f2"
    var cb = "&callback=JSON_CALLBACK";

    return $http.jsonp(api + city + units + appid + cb);
  };
  return obj
});

app.controller('someCtrl', function(WeatherApi) {
  var vm = this;
  WeatherApi.getLoc().then(function(response) {
    vm.location = response.data;
    console.log('Your location:' + JSON.stringify(vm.location));
  })
  WeatherApi.getCurrent('nyc').then(function(response) {
    vm.nycWeather = response.data;
    console.log('Weather in NYC:' + JSON.stringify(vm.nycWeather));
  });
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="app" ng-controller="someCtrl as vm">
</div>

＆＃13;

Javascript Angular工厂解释

1 个答案: