Question

我正在尝试在php中创建一个数组，该数组将通过ajax调用在javascript中解析为json。我注意到用$empty = array()实例化的数组的第一个索引返回{"0":[{..values here..}], "success":true}。理想情况下，我会使用reply.data和reply.success来访问它。答复。成功是有效的，但我似乎无法找到如何创建一个没有0作为第一个索引的数组。

我的php端代码：

    $result = array();
    $record = array();
    $resp = mysqli_query($this->conn, $sql);
    if(mysqli_num_rows($resp)>0){
        while($row = mysqli_fetch_assoc($resp)){
            $record = array();
            foreach($row as $key => $val){
                $record[$key] = $val;
            }
            array_push($result,$record);
            unset($record);
        }
        //return json_encode($result, JSON_PRETTY_PRINT);
        return $result;

当我在javascript中访问它时

 success: function(data){
        data = JSON.parse(data);
        if(data.success==true){  //able to access success with "data.success"
            //there is an empty
            $scope.conn = "connecting to room";
            console.log(data.data.room_id);  //does not work because index is 0
            console.log(JSON.stringify(data));

它返回什么

{"0":[{"room_id":"20","host_id":"","resp_id":"","offer":"","answer":"","status":"0"}],"success":true}

Answer 1

使用此，

$result = array();
$resp = mysqli_query($this->conn, $sql);
if(mysqli_num_rows($resp)>0){
    while($row = mysqli_fetch_assoc($resp)){
        foreach($row as $key => $val){
            $result["data"][$key] = $val
        }
    }
}
//return json_encode($result, JSON_PRETTY_PRINT);
return $result;

Answer 2

我认为你过度复杂化了这个过程

foreach循环似乎是不必要的，因为您只需将$ row加载到数组中即可。

public function xxx()
{
    $result = array();
    $resp = mysqli_query($this->conn, $sql);
    if(mysqli_num_rows($resp)>0) {
        $result['success'] = 'true';

        while($row = mysqli_fetch_assoc($resp)){
            $result['data'][] = $row;
        }

    } else {
        $result['success'] = 'false';
    }
    return $result;
}

// instantiate object 
//$obj = new Whatever the class is called()
echo json_encode($obj->xxx());

使用键值创建一个空数组

2 个答案: