我正在使用barplot()
绘制图表,任何使用beside=TRUE
参数的尝试都会返回错误Error in -0.01 * height : non-numeric argument to binary operator
以下是图表的代码:
combi <- as.matrix(combine)
barplot(combi, main="Top 5 hospitals in California",
ylab="Mortality/Admission Rates", col = heat.colors(5), las=1)
图表的输出是条形图彼此堆叠而不是彼此相邻。
答案 0 :(得分:3)
当combine
是data.frame:
combine <- data.frame(
HeartAttack = c(13.4,12.3,16,13,15.2),
HeartFailure = c(11.1,7.3,10.7,8.9,10.8),
Pneumonia = c(11.8,6.8,10,9.9,9.5),
HeartAttack2 = c(18.3,19.3,21.8,21.6,17.3),
HeartFailure2 = c(24,23.3,24.2,23.8,24.6),
Pneumonia2 = c(17.4,19,17,18.4,18.2)
)
combi <- as.matrix(combine)
barplot(combi, main="Top 5 hospitals in California",
ylab="Mortality/Admission Rates", col = heat.colors(5), las=1, beside = TRUE)
答案 1 :(得分:0)
之前有相同的问题(不同的数据集,tho),然后在我的数据框上使用as.numeric()解决了此问题。我用as.matrix()
将其转换为矩阵。离开as.numeric()"
会导致"Error in -0.01 * height : non-numeric argument to binary operator"
¯\ (ツ) /¯
我的df叫tmp:
> tmp
125 1245 1252 1254 1525 1545 12125 12425 12525 12545 125245 125425
Freq.x.2d "14" " 1" " 1" " 1" " 3" " 2" " 1" " 1" " 9" " 4" " 1" " 5"
Freq.x.3d "13" " 0" " 1" " 0" " 4" " 0" " 0" " 0" "14" " 4" " 1" " 2"
> dim(tmp)
[1] 2 28
> is(tmp)
[1] "matrix" "array" "structure" "vector"
> tmp <- as.matrix(tmp)
> dim(tmp)
[1] 2 28
> is(tmp)
[1] "matrix" "array" "structure" "vector"
> tmp <- as.numeric(tmp)
> dim(tmp)
NULL
> is(tmp)
[1] "numeric" "vector"
barplot(tmp, las=2, beside=TRUE, col=c("grey40","grey80"))