Question

我写了一些代码，想测试一个上传图片功能（尝试将我的iPhone上的图片上传到Mac）

我使用Alamofire4在Xcode8中上传图像，然后创建一个javaWeb来接收Serlvet的图像。

我认为测试后我在Mac上收到了图像的数据，但我无法打开图像。我知道我没有解析DATA（Alamofire4创建的MultipartFormData）。

所以，这是我的问题：如何在Serlvet中解析这个数据来显示真实的图像而不是我的Mac中的imageData 我认为这对javaWeb开发人员来说太容易了，但对我来说很难请告诉我修改。

这是使用Alamofire4的快速代码：

@IBAction func chooseImage(_ sender: UIButton) {
    var picker : UIImagePickerController
    picker = UIImagePickerController()
    picker.delegate = self
    picker.sourceType = UIImagePickerControllerSourceType.photoLibrary
    self.present(picker, animated: true, completion: nil)

}

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    myImage.image = info[UIImagePickerControllerOriginalImage] as! UIImage?
    self.dismiss(animated: true, completion: nil)

}

@IBAction func uploadData(_ sender: UIButton) {
    let imageData = UIImageJPEGRepresentation(myImage.image!, 1)

    imageRename = myText.text!+".jpeg"

    Alamofire.upload(multipartFormData:{(multiData) in
        multiData.append(imageData!, withName: "imageMine", fileName: self.imageRename!, mimeType: "image/*")},
                     usingThreshold:UInt64.init(),
                     to:"http://192.168.0.101:8080/John_SImage/imageServlet",
                     method:.post,
                     headers:nil,
                     encodingCompletion: { encodingResult in
                        switch encodingResult {
                        case .success(let upload, _, _):
                            upload.responseJSON { response in
                                debugPrint(response)
                            }
                        case .failure(let encodingError):
                            print(encodingError)
                        }
    })
}

以下是Servlet（javaWeb）中的代码：

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    System.out.println("1111");
    request.setCharacterEncoding("UTF-8");
    response.setContentType("text/plain;charset=utf-8");
    PrintWriter writer=response.getWriter();    
    InputStream in=request.getInputStream();
    File f = new File("/Users/BC/Desktop/ff.jpeg");
    FileOutputStream fout = new FileOutputStream(f);
    byte[] b=new byte[1024];
    int n=0;
    while ((n=in.read(b))!=-1){
        fout.write(b,0,n);
    }
    fout.close();
    in.close();
    writer.println("Finished uploading files!");
    writer.close();

}

如何在Servlet中解析Alamofire MultipartFormData

0 个答案: