Question

Hullo hullo！我正在研究一个计算输入分数并输出成绩百分比和字母等级的程序。虽然字母评分部分非常简单，但我无法正确完成while循环。目前，我试图通过使用户只输入0到10之间的整数来添加输入陷阱。问题是，每当用户输入必要的输入时，它最终循环并返回输出“请输入完整的号码。”连续

print ( "Enter the homework scores one at a time. Type \"done\" when finished." )
hwCount = 1 
strScore = input ( "HW#" + str ( hwCount ) + " score: " ) 
while ( strScore != int and strScore != "done" )  or\
      ( strScore == int and ( strScore < 0 or strScore >10 )):
         if strScore == int:
            input = int ( input ( "Please enter a number between 0 and 10." ))
         else:
         print ( "Please enter only whole numbers." )
        #End if
         strScore = float ( input ( "enter HW#" + str( hwCount ) + " score:

所以，一旦我弄清楚这一点，我可能会感到非常愚蠢，但我很难过。算法解决方案说明循环while（strScore不是整数，strScore！=“完成”）或（strScore是整数且（strScore <0或strScore> 10）））

提前致谢！

Answer 1

strScore != int不测试该值是否为整数;它检查值是否等于int类型。在这种情况下，您需要not isinstance(strScore, int)。

但是，您应该尽量避免进行直接类型检查。重要的是值的行为就像浮动一样。

print("Enter the homework scores one at a time. Type \"done\" when finished.")
hwCount = 1 
while True:
    strScore = input("HW#{} score: ".format(hwCount))
    if strScore == "done":
        break
    try:
        score = float(strScore)
    except ValueError:
        print("{} is not a valid score, please try again".format(strScore))
        continue

    if not (0 <= score <= 10):
        print("Please enter a value between 1 and 10")
        continue

    # Work with the validated value of score
    # ...
    hwCount += 1

变量循环虽然不是整数

1 个答案: