Question

我试图用C ++制作一本字典，但却无法在＆＃39; =＆＃39;上分割文本文件。分隔符。理想情况下，它将是两个数组。我想采取＆＃39; =＆＃39;的左侧。行的数组[0]和右侧的数组[1]，然后使用数组[0]作为键和数组[1]作为通过预制插入函数的值，例如。 dictionary.insert（array [0]，array [1]）。我已经构建了字典逻辑但是在分割行时遇到了麻烦。

这是我的（可怕的）代码，它没有使用等号作为分隔符，因此将＆＃39; =＆＃39;到数组[1]：

using System;
using System.Collections.Generic;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

namespace demogrid
{
    public partial class grid : System.Web.UI.Page
    {
    GridView gvEmployee = new GridView();

    protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {

        }
        DataTable table = new DataTable();
        table.Columns.Add("Dosage", typeof(int));
        table.Columns.Add("Drug", typeof(string));
        table.Columns.Add("Patient", typeof(string));
        table.Columns.Add("Date", typeof(DateTime));

        // Here we add five DataRows.
        table.Rows.Add(25, "Indocin", "David", DateTime.Now);
        table.Rows.Add(50, "Enebrel", "Sam", DateTime.Now);
        table.Rows.Add(10, "Hydralazine", "Christoff", DateTime.Now);
        table.Rows.Add(21, "Combivent", "Janet", DateTime.Now);
        table.Rows.Add(100, "Dilantin", "Melanie", DateTime.Now);
        BindData(table);
    }
    protected void BindData(DataTable dt)
    {
        gvEmployee.AllowPaging = true;
        gvEmployee.PageSize = 2;
        gvEmployee.AutoGenerateColumns = false;
        gvEmployee.PageIndexChanging += gvEmployee_PageIndexChanging;
        if (dt != null)
        {
            for (int i = 0; i < dt.Columns.Count; i++)
            {
                BoundField boundfield = new BoundField();
                boundfield.DataField = dt.Columns[i].ColumnName.ToString();
                boundfield.HeaderText = dt.Columns[i].ColumnName.ToString();
                gvEmployee.Columns.Add(boundfield);
            }
            Panel1.Controls.Add(gvEmployee);
            gvEmployee.DataSource = dt;
            gvEmployee.DataBind();
            gvEmployee.Width = 600;
            gvEmployee.HeaderStyle.CssClass = "header";
            gvEmployee.RowStyle.CssClass = "rowstyle";

        }
    }

    void gvEmployee_PageIndexChanging(object sender, GridViewPageEventArgs e)
    {
        gvEmployee.PageIndex = e.NewPageIndex;
        gvEmployee.DataBind();

    }


}
}

这是文本文件的前几行：

int main() {

    Dictionary englishToEsperanto;

    ifstream infile("Dictionary.txt");

    string line;
    string arr[2];

    if (infile.is_open())
    {
        while (getline(infile, line))
        {
            int i = 0;
            stringstream ssin(line);
            while (ssin.good() && i < 2) {
                ssin >> arr[i];
                ++i;
            }
            for (i = 0; i < 2; i++) {
                cout << arr[i] << ' ';
            }
                cout << endl;
        }

        infile.close();
    }
    else
    {
        cout << "Error opening file";
    }


    return 0;
}

感谢您的光临。

Answer 1

正如@Thomas在评论中所建议的那样，将'='设置为第一个getline的分隔符，将默认分隔符换行符设置为第二个getline。 Demo.

string before_equal, after_equal;
string arr[2];
while (getline(cin, before_equal, '=') && getline(cin, after_equal))
{
    stringstream ssin1(before_equal);
    stringstream ssin2(after_equal);
    if (ssin1.good() && ssin2.good()) {
        ssin1 >> arr[0];
        ssin2 >> arr[1];
    }
    else continue;
    cout << arr[0] << ' ' << arr[1];
    cout << endl;
}

Answer 2

您可以使用类std::string的标准数据成员函数来执行任务。结果对可以存储在标准类std::vector

中

这是一个示范程序

#include <iostream>
#include <string>
#include <vector>
#include <utility>
#include <cstring>

std::string & trim( std::string &s )
{
    std::string::size_type n = 0;

    while ( n < s.size() && std::isspace( ( unsigned char )s[n] ) ) n++;

    s.erase( 0, n );

    n = s.size();

    while ( n != 0 && std::isspace( ( unsigned char )s[n-1] ) ) n--;

    s.erase( n );
}   

int main() 
{
    const char * s[] =
    {
        "aback, to take = surprizi.",
        "abaft = posta parto.",
        "abandon = forlasi.",
        "abase = humiligi. [error in book: humilgi]",
        "abash = hontigi.",
        "abate (lower) = mallevi.",
        "abate (speed) = malakceli.",
        "abbey = abatejo.",
        "abbot = abato.",
        "abbreviate = mallongigi.",
        "abdicate = demeti la reĝecon.",
        "abdomen = ventro.",
    };


    std::vector< std::pair<std::string, std::string>> dictionary;

    for ( std::string line : s )
    {
        auto n = line.find( '=' );

        std::string key, description;

        if ( n == std::string::npos )
        {
            key = line;
        }
        else
        {
            key = line.substr( 0, n );
            description = line.substr( n + 1 );
        }

        trim( key ); trim( description );

        dictionary.push_back( { key, description } );
    }


    for ( const auto &p : dictionary )
    {
        std::cout << p.first << '\t' << p.second << std::endl;
    }

    return 0;
}

它的输出是

aback, to take  surprizi.
abaft   posta parto.
abandon forlasi.
abase   humiligi. [error in book: humilgi]
abash   hontigi.
abate (lower)   mallevi.
abate (speed)   malakceli.
abbey   abatejo.
abbot   abato.
abbreviate  mallongigi.
abdicate    demeti la reĝecon.
abdomen ventro.

Answer 3

如果您有权访问Boost，Boost.Tokenizer就是您要找的。您可以找到示例here。这将返回一个字符串向量。

否则，您可以使用std::string::find，并按照以下方式实施：

int indOfDelimiter=line.find('=');
std::string Key = line.substr(0,indOfDelimiter);
std::string Value = line.substr(indOfDelimiter+1);

在您的示例中，'='之前和之后都有空格。您可能希望通过更改上面代码中的分隔符来删除它们：

const char *delimiter = " = ";
int indOfDelimiter=line.find(delimiter);
std::string Key = line.substr(0,indOfDelimiter);
std::string Value = line.substr(indOfDelimiter+3);

在＆＃39; =＆＃39;上拆分文本文件分界符逐行C ++

3 个答案: