Question

所以我有这个：

if(isset($_GET['id'])){
$id = $_GET['id'];
$sql = "UPDATE data SET ap = 1 WHERE id = $id" ;
$retval = mysqli_query($dbcon,$sql);
$result = mysqli_query($dbcon,"SELECT ap,id FROM data WHERE id = '$id'") or die(mysql_error());
while ($row = mysqli_fetch_array($result)){
$ap = $row['ap'];
$idd = $row['id'];
}        
}

和：

<div id="<?php if($ap == 1 and $idd == 1){echo:'s1p';}else{echo:'s1';}?>" class="boxabs">
</div> 
<div id="<?php if($ap == 1 and $idd == 2){echo:'s2p';}else{echo:'s2';}?>" class="boxabs">
</div>
<div id="<?php if($ap == 1 and $idd == 3){echo:'s3p';}else{echo:'s3';}?>" class="boxabs">
</div>

当我将URL更改为localhost / bla / index.php？id = 3时，即使div 1具有$ ap == 1，也只有div 3显示为绿色（s1p =绿色div，sp = red div）。此外，当我删除$ idd == x时，它们全部变为绿色。

MySQL（如果你不明白我的意思）：

id|ap 
1 |1  
2 |2
3 |1

Answer 1

我认为这是你想要达到的目标。（未经测试）。

<?php

if(isset($_GET['id'])){
    $id = $_GET['id'];
    $sql = "UPDATE data SET ap = 1 WHERE id = $id" ;
    $retval = mysqli_query($dbcon,$sql);
    $result = mysqli_query($dbcon,"SELECT ap,id FROM data WHERE id = '$id'") or die(mysql_error());

    // set a counter here
    $i=1;
?>

<?php while ($row = mysqli_fetch_array($result)): ?>
    <div id="<?php if($row['ap'] == 1 and $row['idd'] == 1){echo:"s$ip";}else{echo:"s$i";}?>" class="boxabs"></div>
<?php $i++; ?>
<?php endwhile; ?>

保持更改MySQL

1 个答案: