Question

我正在处理一个应用程序，并且遇到了一些困难。我希望将字典中的键作为标签，列表中的四个数字是相应键的值，并显示在按钮中。当我按下一个按钮时，我想更改标签和按钮，以便它转到字典中的下一个元素并继续重复该过程，直到字典中没有更多元素。

到目前为止，这是我的代码：

import tkinter as tk
q_a = {"label":[1,2,3,4],"label 2":[5,6,7,8]}
class ExampleApp(tk.Tk):
    def __init__(self):
        tk.Tk.__init__(self)
        self.label = tk.Label(self)
        self.label.pack()
        self.remaining = len(q_a)
        self.countdown(self.remaining-1)

    def loop(self, remaining=None):
        if self.remaining <= 0:
            self.label.configure(text="The end")
        else:
            self.label.configure(text=(list(q_a.keys())[self.remaining-1]))
            dictionary_index = list(q_a.keys())[self.remaining-1]
            self.remaining = self.remaining - 1
            button1 = tk.Button(self, text=q_a[dictionary_index][0],
                           command=lambda: self.loop).pack()
            button2 = tk.Button(self, text=q_a[dictionary_index][1],
                           command=lambda: self.loop).pack()
            button3 = tk.Button(self, text=q_a[dictionary_index][2],
                           command=lambda: self.loop).pack()
            button4 = tk.Button(self, text=q_a[dictionary_index][3],
                           command=lambda: self.loop).pack()


if __name__ == "__main__":
    app = ExampleApp()
    app.mainloop()

Answer 1

首先我创建空标签和按钮，然后我使用override func layoutSubviews() { // self.frame.size.width = 300 //self.frame = CGRect(x: self.frame.origin.x, y: self.frame.origin.y, width: 200, height: self.frame.height) }仅更改标签和按钮上的文字。

我使用list而不是dictionary loop来控制列表中哪些数据我必须用作文本。

self.current

BTW：最终你可以将按钮保持为列表import tkinter as tk q_a = [ ["label 1", [1,2,3,4]], ["label 2", [5,6,7,8]], ] class ExampleApp(tk.Tk): def __init__(self): tk.Tk.__init__(self) self.label = tk.Label(self) self.label.pack() self.button1 = tk.Button(self, command=self.loop) self.button1.pack() self.button2 = tk.Button(self, command=self.loop) self.button2.pack() self.button3 = tk.Button(self, command=self.loop) self.button3.pack() self.button4 = tk.Button(self, command=self.loop) self.button4.pack() self.last = len(q_a) self.current = -1 # set first text # because `self.current = -1` then it use `self.current = 0` self.loop() def loop(self): # get next element from list self.current += 1 if self.current == self.last: self.label.configure(text="The end") # hide buttons self.button1.forget() self.button2.forget() self.button3.forget() self.button4.forget() else: self.label['text'] = q_a[self.current][0] self.button1['text'] = q_a[self.current][1][0] self.button2['text'] = q_a[self.current][1][1] self.button3['text'] = q_a[self.current][1][2] self.button4['text'] = q_a[self.current][1][3] if __name__ == "__main__": app = ExampleApp() app.mainloop()并使用button[0], etc,循环来更改所有按钮上的文本或隐藏所有按钮。

BTW：为了提高可读性，您可以使用带有词典的列表

for

和

q_a = [
    {"q": "label 1", "a": [1,2,3,4]},
    {"q": "label 2", "a": [5,6,7,8]},
]

甚至

    else:
        self.label['text'] = q_a[self.current]["q"]
        self.button1['text'] = q_a[self.current]["a"][0]
        self.button2['text'] = q_a[self.current]["a"][1]
        self.button3['text'] = q_a[self.current]["a"][2]
        self.button4['text'] = q_a[self.current]["a"][3]

动态更新tkinter中按钮上的文本

1 个答案: