Question

我在C ++中为一个确定的二维数组（用数字代表一个像素中颜色的数值 - ＆gt; matrizGrey）编写直方图。你必须通过参数（argv [4]）引入直方图将具有的部分的数量，并且范围在0到255之间。因此，根据部分的数量，直方图将发生变化。我抓住了它是如何工作的（比较范围的第一个元素和下一个元素之间的矩阵元素）但我的问题是我不能递归。以下代码显示了我此时的进展：

  if (strcmp(argv[1], "-u") == 0 && *argv[2] == '0' && strcmp(argv[3], "-t") == 0) {
  unsigned int sections = atoi(argv[4]);
  unsigned int histogram[sections] = {};
  unsigned int k = 0;
  float limits[sections];
  float value = (float)255/sections;

  if (sections > 0) {
    cout << "The number of sections " << sections << "\n";
    cout << "Each section is " << value << "\n";

    cout << "The array of limits is : " << "\n";  
    for (unsigned int i = 0; i < sections; ++i) {
        limits[i] = value*i;
        cout << limits[i] << " ";
    }

       for (unsigned int i = 0; i < length; ++i) {
        for (unsigned int j = 0; j < width; ++j) {
            if (matrizGrey[i][j] >= 0 && matrizGrey[i][j] < limits[1] ) {
                histogram[0] = histogram[0]+1;
            }
            else if (matrizGrey[i][j] >= limits[1] && matrizGrey[i][j] < limites[2] ) {
                histogram[1] = histogram[1]+1;
            }
            else if (matrizGrey[i][j] >= limits[2] && matrizGrey[i][j] < limites[3] ) {
                histogram[2] = histogram[2]+1;
            }

        }
       }

    cout << endl;
    cout << "The final result will be : " << "\n";
    for (unsigned int i = 0; i < sections; ++i) {
        //histogram[i] = 0;
        cout << histogram[i] << " ";
    }

例如，使用此＆＃34;图像＆＃34;：matrizGrey [0] [0] = 100，matrizGrey [0] [1] = 200，matrizGrey [1] [0] = 125，matrizGrey [1 ] [1] = 0，matrizGrey [2] [0] = 255， matrizGrey [2] [1] = 7，

如果我引入2的节号（这意味着我的范围将是[0,127]，[128,255]），结果必须是＆＃34; 4 2＆＃34;。这是一个小例子，但我需要为随机数量的部分和随机数量的像素执行此操作。

感谢您的关注。

Answer 1

我认为我找到了一个更好的解决方案，但我仍然有问题，因为如果部分的数量很大，它不会显示所有元素。

if (strcmp(argv[1], "-u") == 0 && *argv[2] == '0' && strcmp(argv[3], "-t") == 0) {
  unsigned int sections = atoi(argv[4]);
  unsigned int histogram[sections] = {};
  unsigned int k = 0;
  float limits[sections];
  float value = (float)255/sections;

  if (sections > 0) {
    cout << "The number of sections " << sections << "\n";
    cout << "Each section is " << value << "\n";

    cout << "The array of limits is : " << "\n";   
    for (unsigned int i = 0; i < sections; ++i) {
        limits[i] = value*i;
        cout << limits[i] << " ";
    }

      for (unsigned int i = 0; i < length; ++i) {
        for (unsigned int j = 0; j < width; ++j) {
            px = matrizGrey[i][j];
            k = 0;
            while (k < sections) {
                if (px > limits[k] && px <= limits[k+1] ) {
                histogram[k]++;
                break;
                }
                else {
                k++;
                }   
            }
        }
      } 

    cout << endl;
    cout << "The final result will be: " << "\n";
    for (unsigned int i = 0; i < sections; ++i) {
        //histogram[i] = 0;
        cout << histogram[i] << " ";
    }

    cout << "\n";
  }

C ++中的直方图

1 个答案: