Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs)处理Button1.Click
With OpenFileDialog1
.FileName = String.Empty
.InitialDirectory = "C:\"
.Title = "Open Excel File"
.Filter = "Excel 97-2003|*.xls|Excel 2007|*.xlsx"
End With
Dim result As DialogResult = OpenFileDialog1.ShowDialog()
If result = Windows.Form.DialogResult.OK Then
Try
TextBox1.Text = OpenFileDialog1.FileName
GetExcelSheetNames(TextBox1.Text)
Catch ex As Exception
MsgBox("Error : " & ex.Message)
End Try
End If
End Sub
答案 0 :(得分:3)
Public Class Form1
Private loginLabel As String
Public Sub New(ByVal loginParameter As String)
InitializeComponent()
Me.loginLabel = loginParameter
End Sub
End Class
并以您的登录表单:
dim frm as new Form1(label.Text)