Question

我有一个numpy-array

   X_test =  [array([1,2]), array([3,4]), array([5,6]), array([7,8]), array([9,10]), array([11,12])]

我会删除每一行以获得一个新数组：

[array([3,4]), array([5,6]), array([7,8]), array([9,10]), array([11,12])]
[array([1,2]), array([5,6]), array([7,8]), array([9,10]), array([11,12])]
[array([1,2]), array([3,4]), array([7,8]), array([9,10]), array([11,12])]
[array([1,2]), array([3,4]), array([5,6]), array([9,10]), array([11,12])]
[array([1,2]), array([3,4]), array([5,6]), array([7,8]), array([11,12])]
[array([1,2]), array([3,4]), array([5,6]), array([7,8]), array([9,10])]

我曾尝试过这样的阵列：

for i in range(len(X_test)):
    np.delete(X_test, i)
    print X_test

Answer 1

[X_test[:i] + X_test[i+1:] for i in range(len(X_test))]

为您提供包含所需元素的列表

如何从np中删除每个元素。数组来获取没有这个合适元素的数组？

1 个答案: