Question

我的表格tbl_commaseperate包含ID，MONNAME，IP和POLICY列，其值为：

ID |  MONNAME | IP    | POLICY
-------------------------------
X  |  NOV     | 1,2,3 | 4,5,6,7

IP和POLICY的逗号分隔值。

我想要的结果如下所示：

ID | MONNAME | IP    | POLICY
------------------------------
X  | NOV     |  1    |  4
X  | NOV     |  2    |  5
X  | NOV     |  3    |  6
X  | NOV     |  null |  7

Answer 1

请试试这个。

创建一个用于拆分逗号分隔字符串的函数。

CREATE FUNCTION [dbo].[fnSplit](
    @sInputList VARCHAR(max) -- List of delimited items
  , @sDelimiter VARCHAR(max) = ',' -- delimiter that separates items
) RETURNS @List TABLE (SplitValue VARCHAR(max))

BEGIN
DECLARE @sItem VARCHAR(max)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
    BEGIN
        SELECT
          @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
          @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))

         IF LEN(@sItem) > 0
            INSERT INTO @List SELECT @sItem
    END

IF LEN(@sInputList) > 0
    INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END

然后像这样编写你的查询。

select * from (
    select SplitValue,ROW_NUMBER() over(order by SplitValue) rowNo FROM dbo.fnSplit('1,2,3',',') 
) as a 
full join (
    select SplitValue,ROW_NUMBER() over(order by SplitValue) rowNo FROM dbo.fnSplit('4,5,6,7',',')
) as b on a.rowNo=b.rowNo

用硬核字符串替换你的列。 注意：您也可以使用查询而不是函数进行编写。

Answer 2

CREATE TABLE #Table ( ID VARCHAR(100),MONNAME VARCHAR(100), IP VARCHAR(100) , POLICY VARCHAR(100))
INSERT INTO #Table (ID ,MONNAME, IP, POLICY)SELECT 'X','NOV',1,2,3,4','4,5,6,7'
;WITH _CTE ( _id ,_MONNAME , _IP   , _POLICY , _RemIP , _RemPOLICY) AS (
SELECT ID ,MONNAME , SUBSTRING(IP,0,CHARINDEX(',',IP)),       SUBSTRING(POLICY,0,CHARINDEX(',',POLICY)),
SUBSTRING(IP,CHARINDEX(',',IP)+1,LEN(IP)),
SUBSTRING(POLICY,CHARINDEX(',',POLICY)+1,LEN(POLICY))
FROM #Table
UNION ALL
SELECT _id ,_MONNAME , CASE WHEN CHARINDEX(',',_RemIP) = 0 THEN _RemIP ELSE
SUBSTRING(_RemIP,0,CHARINDEX(',',_RemIP)) END, CASE WHEN CHARINDEX(',',_RemPOLICY) = 0 THEN _RemPOLICY ELSE SUBSTRING(_RemPOLICY,0,CHARINDEX(',',_RemPOLICY)) END,
CASE WHEN CHARINDEX(',',_RemIP) = 0 THEN '' ELSE SUBSTRING(_RemIP,CHARINDEX(',',_RemIP)+1,LEN(_RemIP)) END,
CASE WHEN CHARINDEX(',',_RemPOLICY) = 0 THEN '' ELSE SUBSTRING(_RemPOLICY,CHARINDEX(',',_RemPOLICY)+1,LEN(_RemPOLICY)) END
FROM _CTE WHERE _RemIP <> '' OR _RemPOLICY <> ''
)
SELECT _id id,_MONNAME MONNAME, _IP IP , _POLICY POLICY 
FROM _CTE

Answer 3

的Oracle

with        r (id,monname,ip,policy,n,max_tokens)
            as
            (
                select      id,monname,ip,policy
                           ,1
                           ,greatest (nvl(regexp_count(ip,'[^,]+'),0),nvl(regexp_count(policy,'[^,]+'),0))            
                from        tbl_commaseperate

                union all

                select      id,monname,ip,policy
                           ,n+1
                           ,max_tokens                  
                from        r                
                where       n < max_tokens
                )

select      r.id
           ,r.monname
           ,regexp_substr (ip    ,'[^,]+',1,n)  as ip
           ,regexp_substr (policy,'[^,]+',1,n)  as policy

from        r
;

Answer 4

输出没有特别的顺序。此外，在您想要的输出中，您似乎并不关心哪一对是第一对，哪一对等等（但如果需要，可以在查询中保留）。

我添加了一行以进行更多测试;我policy为NULL - 这就是我意识到我需要coalesce()周围的regexp_count。

with
     inputs ( id ,monname, ip , policy ) as (
       select 'X', 'NOV', '1,2,3' , '4,5,6,7' from dual union all
       select 'X', 'DEC', '6,3,8', null      from dual
     )
-- end of test data; solution (SQL query) begins below this line
select id, monname,
       regexp_substr(ip    , '[^,]+', 1, level) as ip,
       regexp_substr(policy, '[^,]+', 1, level) as policy
from   inputs
connect by level <= 1 + greatest( coalesce(regexp_count(ip    , ','), 0),
                                  coalesce(regexp_count(policy, ','), 0)  )
    and prior id = id
    and prior monname = monname
    and prior sys_guid() is not null
;

ID MONNAME IP    POLICY
-- ------- ----- -------
X  DEC     6            
X  DEC     3            
X  DEC     8            
X  NOV     1     4      
X  NOV     2     5      
X  NOV     3     6      
X  NOV           7      

 7 rows selected

逗号将多列中的值分隔为行

4 个答案:

的Oracle