Question

我有一组数组，我在指定的时间间隔内在imageview中显示。当我点击图像时，我想要在另一个活动中显示该图像。我怎么能这样做

代码： -

int[] imageArray = {R.drawable.amazon, R.drawable.app_me,
        R.drawable.borabora, R.drawable.dubai};
public void showImage(){
    m_oHandler = new Handler();
    Runnable oRunnable = new Runnable() {
        int i = 0;

        @Override
        public void run() {
            img.setImageResource(imageArray[i]);
            i++;
            if (i > imageArray.length - 1) {
                i = 0;
            }
            img.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    //  Didn't know where to go
                    Intent intent = new Intent(MainActivity.this, Second.class);
                    intent.putExtra("BitmapImage", imageArray);
                }
            });
            m_oHandler.postDelayed(this, 6000);

        }
    };
    m_oHandler.postDelayed(oRunnable, 6000);
}

Answer 1

不传递Bitmap对象而是传递可绘制资源的id。

Intent intent = new Intent(MainActivity.this, Second.class);
intent.putExtra("image_res_ids", CollectonUtils.join("/", imageArray);

在Second活动中，

getIntent().getExtra("image_res_ids");

获取图像资源ID数组。

Answer 2

当我点击图片时，我希望在另一个活动中显示该图像。

使用img setTag()方法保存当前的可绘制ID，并使用getTag()

点击视图将其恢复

1。使用setTag设置drawable id：

....
img.setImageResource(imageArray[i]);
img.setTag(imageArray[i]);
....

2。在onClick方法中从v获取ID：

int click_drawable_id=Integer.parseInt(v.getTag().toString());
intent.putExtra("clicked_img_draw_id", click_drawable_id);

现在，不要传递imageArray数组，只需使用clicked_img_draw_id获取可绘制的ID并将其传递给setImageResource，以便在另一个活动中显示点击的图片。

Answer 3

你的图像是可绘制的资源，它们只不过是一个int。所以你绝对可以在Intent中将它们作为额外内容传递。

Answer 4

您可以将该数组作为额外发送，然后使用getIntent().getIntArrayExtra(EXTRA_IMAGE)

获取它

有关详细信息，请查看Intents

Answer 5

使用setTag保存索引/资源ID，即img.setTag（index），如下所示。然后，您可以从标记中删除索引/资源ID，并将其作为额外的意图传递

 @Override
        public void run() {
            img.setImageResource(imageArray[i]);
            img.setTag(i)
            i++;
            //your code
            img.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    //  Didn't know where to go
                    Intent intent = new Intent(MainActivity.this, Second.class);
                    intent.putExtra("IMAGE_RESOURCE", img.getTag());
                }
            });

Answer 6

尝试发送所选图片的位置

Intent i = new Intent(getApplicationContext(), FullImageActivity.class);
                // passing array index
                i.putExtra("id", position);
                startActivity(i);

获得意图

Intent i = getIntent();

        // Selected image id
        int position = i.getExtras().getInt("id");
        ImageAdapter imageAdapter = new ImageAdapter(this);

        ImageView imageView = (ImageView) findViewById(R.id.full_image_view);
        imageView.setImageResource(imageAdapter.mThumbIds[position]);

选中此项以获取更多http://www.androidhive.info/2012/02/android-gridview-layout-tutorial/

Answer 7

If you want to pass single image to next activity, than in your case, only pass image index like

Intent intent = new Intent(MainActivity.this, Second.class);
                    intent.putExtra("BitmapImage", imageArray[i]);

and on next activity get it. like 
int image_id= getIntent().getIntExtra("BitmapImage",0);

this image_id is your selected image resouce id  and you can set this as setImageresouce to image view.

Answer 8

previewView = (ImageView) findViewById(R.id.imgPostIssue);

第一项活动

Intent intent = new Intent(AddNewIssue.this, PostNewIssue.class);
        intent.putExtra("picture", byteArray);
        finish();
        startActivity(intent);

第二项活动

Bundle extras = getIntent().getExtras();
        if (extras != null) {
            byte[] byteArray = extras.getByteArray("picture");
            if (byteArray != null) {
                Bitmap bmp = BitmapFactory.decodeByteArray(byteArray, 0, byteArray.length);
                ImageView image = (ImageView) findViewById(R.id.imgPostIssue);

                image.setImageBitmap(bmp);
            }
        }

试试这个，它肯定会有效。希望它能帮到你。

Answer 9

尝试使用setTag()。看看这个

BitmapCache.java

public class BitmapCache {

    private static SparseArray<Bitmap> _bitmapCache = new SparseArray<>();

    public static void fillBitmapCache(@NonNull Resources resources) {
        if (null == _bitmapCache)
            _bitmapCache = new SparseArray<>();

        if (_bitmapCache.indexOfKey(R.drawable.amazon) < 0)
            _bitmapCache.append(R.drawable.amazon, BitmapFactory.decodeResource(resources, R.drawable.amazon));

        if (_bitmapCache.indexOfKey(R.drawable.app_me) < 0)
            _bitmapCache.put(R.drawable.app_me, BitmapFactory.decodeResource(resources, R.drawable.app_me));

        if (_bitmapCache.indexOfKey(R.drawable.borabora) < 0)
            _bitmapCache.put(R.drawable.borabora, BitmapFactory.decodeResource(resources, R.drawable.borabora));

        if (_bitmapCache.indexOfKey(R.drawable.dubai) < 0)
            _bitmapCache.put(R.drawable.dubai, BitmapFactory.decodeResource(resources, R.drawable.dubai));
    }

    public static Bitmap getAt(int position) {
        return get(keyAt(position));
    }

    public static int keyAt(int position) {
        return _bitmapCache.keyAt(position);
    }

    public static Bitmap get(@DrawableRes int resId) {
        return _bitmapCache.get(resId);
    }

    public static boolean has(@DrawableRes int resId) {
        return _bitmapCache.indexOfKey(resId) < 0;
    }

    public static void append(@DrawableRes int resId, @NonNull Resources resources) {
        _bitmapCache.append(resId, BitmapFactory.decodeResource(resources, resId));
    }

    public static void put(@DrawableRes int resId, @NonNull Resources resources) {
        _bitmapCache.put(resId, BitmapFactory.decodeResource(resources, resId));
    }

    public static int size() {
        return _bitmapCache.size();
    }
}

活动优先

 private void showImage() {
        BitmapCache.fillBitmapCache(getResources());

        m_oHandler = new Handler();
        Runnable oRunnable = new Runnable() {
            int i = 0;

            @Override
            public void run() {
                img.setImageBitmap(BitmapCache.getAt(i));
                img.setTag(BitmapCache.keyAt(i));
                i++;
                if (i >= BitmapCache.size()) {
                    i = 0;
                }
                img.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        if (null != v.getTag()) {
                            int resId = (int) v.getTag();
                            Intent intent = new Intent(MainActivity.this, Second.class);
                            intent.putExtra("BitmapImage", resId);
                        }
                    }
                });
                m_oHandler.postDelayed(this, 6000);

            }
        };
        m_oHandler.postDelayed(oRunnable, 6000);
    }

第二项活动

private void displayImageOnSecond() {
        Bundle bundle = getIntent().getExtras();
        int resId = bundle.getInt("BitmapImage", 0);

        if (resId > 0) {
            secondImage.setImageBitmap(BitmapCache.get(resId));
        }
    }

另外，我建议使用ViewPager并将其自定义为自动旋转而不是您当前使用的旋转。如果Runnable已被销毁，Activity可能会导致内存泄漏

如何将图像发送到android中的另一个活动？

9 个答案: