Question

我是laravel 5.3的新手，请帮我解决这个问题。我需要通过三个参数来过滤数据库中的匹配记录，例如类别，位置，搜索字符串。这是我的代码：

$results = DB::table('ads')
                ->join('category', 'category.categoryID', '=', 'ads.categoryID')
                ->join('sub_categories', 'sub_categories.subCategoryID', '=', 'ads.subCategoryID')
                ->join('site_users', 'site_users.siteUserID', '=', 'ads.createdBy')
                ->join('location', 'location.locationID', '=', 'site_users.location')
                ->select('ads.*', 'category.categoryName', 'sub_categories.subCategoryName', 'location.locationName')
                ->where([
                    'ads.title', 'like', '%' . $data['q'] . '%',
                    'ads.isActive', 1
                ])
                ->orWhere([
                    'location.locationName', 'like', '%' . $data['loc'] . '%',
                    'category.categoryName', 'like', '%' . $data['cat'] . '%'
                ])
                ->toSql();
        dd($results);

我调试了这段代码的结果是：

"select `ads`.*, `category`.`categoryName`, `sub_categories`.`subCategoryName`, `location`.`locationName` from `ads` inner join `category` on `category`.`categoryID` = `ads`.`categoryID` inner join `sub_categories` on `sub_categories`.`subCategoryID` = `ads`.`subCategoryID` inner join `site_users` on `site_users`.`siteUserID` = `ads`.`createdBy` inner join `location` on `location`.`locationID` = `site_users`.`location` where (`0` = ? and `1` = ? and `2` = ? and `3` = ? and `4` = ?) or (`0` = ? and `1` = ? and `2` = ? and `3` = ? and `4` = ? and `5` = ?)"

如何使用多个类似操作执行简单搜索功能请给我一个指南。感谢

Answer 1

这样的事情：

  $results = DB::table('ads')
            ->join('category', 'category.categoryID', '=', 'ads.categoryID')
            ->join('sub_categories', 'sub_categories.subCategoryID', '=', 'ads.subCategoryID')
            ->join('site_users', 'site_users.siteUserID', '=', 'ads.createdBy')
            ->join('location', 'location.locationID', '=', 'site_users.location')
            ->select('ads.*', 'category.categoryName', 'sub_categories.subCategoryName', 'location.locationName')
            ->where(function ($query) use ($data){
              $query->where('ads.title', 'LIKE', '%'.$data['q'].'%')
                   ->orWhere('location.locationName', 'LIKE', '%'.$data['loc'].'%')
                   ->orWhere('category.categoryName', 'LIKE', '%'.$data['cat'].'%')                        
            })
            ->where([
                'ads.isActive' => 1
            ])
            ->toSql();

希望有所帮助

Docs

使用Laravel 5.3从MySql数据库搜索记录

1 个答案: