Question

使用此代码仅在第一次启动应用时才发出Activity加载但遇到问题，假设第一次启动的Activity为{ {1}}，WebView正在加载，WebView完成得太快。这是我第一次使用Activity加载的代码。

Activity

这是第一次加载的活动的代码

count = readSharedPreferenceInt("cntSP","cntKey");
if(count==0){
    Intent intent = new Intent();
    intent.setClass(MainActivity.this, TemporaryActivity.class);
    startActivity(intent);
    count++;
    writeSharedPreference(count,"cntSP","cntKey");
}

//Read from Shared Preferance
public int readSharedPreferenceInt(String spName,String key){
    SharedPreferences sharedPreferences = getSharedPreferences(spName,Context.MODE_PRIVATE);
    return tempInt = sharedPreferences.getInt(key, 0);
}     

//write shared preferences in integer
public void writeSharedPreference(int ammount,String spName,String key ){
    SharedPreferences sharedPreferences = getSharedPreferences(spName, Context.MODE_PRIVATE);
    SharedPreferences.Editor editor = sharedPreferences.edit();

    editor.putInt(key, ammount);
    editor.commit();
}

Answer 1

好。您已实施此方法onPageFinished()，并在该方法内的onCreate()内执行此片段。

public void onPageFinished(WebView view, String url) {
    //You code, which you had put inside onCreate() should go here.
}

修改

Intent intent = new Intent(MainActivity.this, TemporaryActivity.class); startActivity(intent); ...

新编辑

public class C01561 extends WebViewClient { private Context context; C01561(Context context) { this.context = context; } public void onPageFinished(WebView view, String url) { Reg_Status.this.pBar.setVisibility(ProgressBar.INVISIBLE); Intent intent = new Intent(context, TemporaryActivity.class); startActivity(intent); } }

当您创建WebViewClient的实例时，请确保传递MainActivity上下文。

webView.setWebViewClient(new C01561(MainActivity.this));

Answer 2

创建一个处理程序以延迟第二个活动的开始。

new Handler().postDelayed(new Runnable() {


        @Override
        public void run() {
            Intent intent = new Intent();
            intent.setClass(MainActivity.this, TemporaryActivity.class);
            startActivity(intent);

        }
    }, TIME_OUT);

现在，在if条件中调用此处理程序并相应地设置TIME_OUT。

第一次启动时第一次加载时，活动完成得太快

2 个答案: