Question

我们如何更改表单的结构以使输入超出标签当我的表单渲染将显示如下：

<p>
<label for="id_form-0-food_name_0"><input checked="checked" id="id_form-0-food_name_0" name="form-0-food_name" value="" type="radio"> (Nothing)</label>
<label for="id_form-0-food_name_1"><input id="id_form-0-food_name_1" name="form-0-food_name" value="1" type="radio"> خوراک مرغ</label>
<label for="id_form-0-food_name_2"><input id="id_form-0-food_name_2" name="form-0-food_name" value="2" type="radio"> خوراک لوبیا</label>
<label for="id_form-0-food_name_3"><input id="id_form-0-food_name_3" name="form-0-food_name" value="3" type="radio"> فسنجون</label>
</p>

但是我需要从input s标记中进行label渲染。像这样：

<p>
<input checked="checked" id="id_form-0-food_name_0" name="form-0-food_name" value="" type="radio"><label for="id_form-0-food_name_0"> (Nothing)</label>
<input id="id_form-0-food_name_1" name="form-0-food_name" value="1" type="radio"><label for="id_form-0-food_name_1"> خوراک مرغ</label>
<input id="id_form-0-food_name_2" name="form-0-food_name" value="2" type="radio"><label for="id_form-0-food_name_2"> خوراک لوبیا</label>
<input id="id_form-0-food_name_3" name="form-0-food_name" value="3" type="radio"><label for="id_form-0-food_name_3"> فسنجون</label>
</p>

我的forms.py:

class Reserve(ModelForm):
    food_name = forms.ModelChoiceField(
        queryset=Food.objects.all(), 
        widget=forms.RadioSelect(renderer=RadioFieldWithoutULRenderer), 
        empty_label="(Nothing)",
        # label=''
        )
    class Meta:
        model = Reservation
        fields = ('food_name',)

和form.html

<form method="post">
{% csrf_token %}

{% for form in formset %}

<p>
  <input name="group1" type="radio" id="test1" value="" />
  {{ form.food_name  }}
</p>

{% endfor %}

<button type="submit" class="btn btn-default">Submit</button>

Answer 1

As shown in this question，您可以使用自定义模板创建自己的窗口小部件：

在模板文件夹中创建模板文件（例如 my_project / my_app / templates / my_app / widgets / radio_option.html ）：

{% include "django/forms/widgets/input.html" %}{% if widget.wrap_label %}<label{% if widget.attrs.id %} for="{{ widget.attrs.id }}"{% endif %}>{{ widget.label }}</label>{% endif %}

（此模板是从 django / forms / templates / django / forms / widgets / input_option.html 复制并稍加修改的，该模板默认用于收音机小部件。）

在您的应用中创建自定义小部件：

class MyRadioSelect(django.forms.RadioSelect):
    option_template_name = "my_app/widgets/radio_option.html"

使用MyRadioSelect代替RadioSelect

django - 更改表单的结构，使输入超出标签

1 个答案: