我有一个可以编辑和保存的HTML表格。保存后,我希望它更新对数据库所做的任何更改。现在我拥有它,以便每当表保存时,它会自动将“23”保存到“Buyer_ID”列中,因为它是硬编码的。但是,我怎样才能得到它以便它不被硬编码并将读取并保存在表格中输入,添加或编辑的任何值?
HTML / PHP代码:
<div id="dialog-form" title="Add Vendor">
<p class="validateTips">All form fields are required.</p>
<form>
<fieldset>
<label for="mr_name">Vendor</label>
<input type="text" name="mr_name" id="mr_name" class="text ui-widget-content ui-corner-all">
<label for="buyer_id">Buyer ID</label>
<input type="text" name="buyer_id" id="buyer_id" class="text ui-widget-content ui-corner-all">
<label for="poc_n">POC Name</label>
<input type="text" name="poc_n" id="poc_n" class="text ui-widget-content ui-corner-all">
<label for="poc_p">POC Email</label>
<input type="text" name="poc_e" id="poc_e" class="text ui-widget-content ui-corner-all">
<label for="poc_p">POC Phone</label>
<input type="text" name="poc_p" id="poc_p" class="text ui-widget-content ui-corner-all">
<!-- Allow form submission with keyboard without duplicating the dialog button -->
<input type="submit" id="submit" tabindex="-1" style="position:absolute; top:-1000px">
</fieldset>
</form>
</div>
<form method="post" action="ajaxsubmit.php">
<div id="users-contain" class="ui-widget">
<table id="html_master" class="ui-widget ui-widget-content">
<thead>
<tr class="ui-widget-header">
<td>ID</td>
<td>Vendor</td>
<td>Buyer ID</td>
<td>POC Name</td>
<td>POC Email</td>
<td>POC Phone</td>
<td>Edit/Delete</td>
</tr>
</thead>
<tbody>
<?php
foreach ($dbh->query($sql) as $rows){
?>
<tr>
<td class="mr_id" contenteditable="false"><?php echo intval ($rows['MR_ID'])?></td>
<td class="mr_name" name="field" contenteditable="false"><?php echo $rows['MR_Name']?></td>
<td class="buyer_id" contenteditable="false"><?php echo $rows['Buyer_ID']?></td>
<td class="poc_n" contenteditable="false"><?php echo $rows['MR_POC_N']?></td>
<td class="poc_e" contenteditable="false"><?php echo $rows['MR_POC_E']?></td>
<td class="poc_p" contenteditable="false"><?php echo $rows['MR_POC_P']?></td>
<td><input type="button" class="edit" name="edit" value="Edit">
<input type="button" class="deactivate" name="deactivate" value="Deactivate"></td>
</tr>
<?php
}
?>
</tbody>
<input type="button" class="create-user" value="Add Row">
<input type="submit" value="Save Table" class="save">
</table>
</div>
<input type="button" class="create-user" value="Add Row">
<input type="submit" value="Save Table" class="save">
</form>
JavaScript保存功能:
// ----- Save Table -----
$(document).on("click", ".save", function () {
// ------ Confirmation box in order to deactivate/activate row -----
if (confirm('Saving will update the entire table. Are you sure you want to save?')) {
var tabledata=[];
$( "#html_master tbody tr" ).each(function( index ) {
tabledata[index] = {
mr_id: $( this ).find("td.mr_id").text(),
mr_name: $( this ).find("td.mr_name").text(),
buyer_id: $( this ).find("td.buyer_id").text(),
poc_n: $( this ).find("td.poc_n").text(),
poc_e: $( this ).find("td.poc_e").text(),
poc_p: $( this ).find("td.poc_p").text()
};
});
}
});
Ajax提交代码:
<?php
$host="xxxxxxxx";
$dbName="xxxxx";
$dbUser="xxxxxxxxxxx";
$dbPass="xxxxxxxx";
$dbh = new PDO( "sqlsrv:server=".$host."; Database=".$dbName, $dbUser, $dbPass);
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
try {
$conn = new PDO( "sqlsrv:server=".$host."; Database=".$dbName, $dbUser, $dbPass);
$conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$qry=$conn->prepare('INSERT INTO Stage_Rebate_Master (Buyer_ID) VALUES (23)');
$qry->execute(Array("23" => $field));
} catch (PDOException $e) {
echo 'Error: ' . $e->getMessage() . " file: " . $e->getFile() . " line: " . $e->getLine();
exit;
}
?>
<form method="post">
<input type="text" name="field" value="<?php print $field; ?>">
<input type="submit" name="youraction" value="save">
</form>
答案 0 :(得分:0)
删除所有<form>
元素并仅使用AJAX。将您的JS on click
处理程序更改为此。
$(document).on("click", ".save", function () {
if (confirm('Saving will update the entire table. Are you sure you want to save?')) {
var tabledata=[];
$( "#html_master tbody tr" ).each(function( index ) {
tabledata[index] = {
mr_id: $( this ).find("td.mr_id").text(),
mr_name: $( this ).find("td.mr_name").text(),
buyer_id: $( this ).find("td.buyer_id").text(),
poc_n: $( this ).find("td.poc_n").text(),
poc_e: $( this ).find("td.poc_e").text(),
poc_p: $( this ).find("td.poc_p").text()
}
});
$.ajax({
url: 'yourPHPfile.php', //Change this to your PHP file
data: {tableData: tabledata},
type: 'POST',
dataType: 'JSON',
error: function (request, error) {
console.log(error);
},
success: function (data) {
console.log(data);
}
});
}
});
<强> PHP 强>
<?php
$host="xxxxxxxx";
$dbName="xxxxx";
$dbUser="xxxxxxxxxxx";
$dbPass="xxxxxxxx";
$dbh = new PDO( "sqlsrv:server=".$host."; Database=".$dbName, $dbUser, $dbPass);
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$tableArray = $_POST['tableData'];
try {
$conn = new PDO( "sqlsrv:server=".$host."; Database=".$dbName, $dbUser, $dbPass);
$conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
//Loop through each Array object and grab each objects value for the specified database column
foreach($tableArray as $key=>$value){
$qry=$conn->prepare('UPDATE Stage_Rebate_Master SET `Mr_Name`=?,`Buyer_ID`=?,`Poc_n`=?,`Poc_e`=?,`Poc_p`=? WHERE `Mr_Id`=?');
$qry->execute(Array($value->mr_name,$value->buyer_id,$value->poc_n,$value->poc_e,$value->poc_p,$value->mr_id));
}
} catch (PDOException $e) {
echo 'Error: ' . $e->getMessage() . " file: " . $e->getFile() . " line: " . $e->getLine();
exit;
}
?>
这使用AJAX post方法将JSON对象数组传递给PHP。更改prepare
语句中的列名称以匹配数据库列。一旦您点击&#34;确认&#34;它将使用HTML表格中的所有数据更新整个数据库表。在你的&#34;保存&#34;对话。
我建议你在PDO准备好的陈述上做更多的阅读,因为你现在的内容甚至都没有接近准备好的陈述。
这也假设mr_id
列是您的主键。如果不是,您需要相应地进行这些更改。