Question

我有两张桌子。一个是Cost_Table，另一个是Hire_Table。

Cost_Table 的布局如下所示：

 sitename   cost   impressions  deliverydate
  Yahoo     100      10000       2016-01-01
  Yahoo     200      20000       2016-01-02
  Google    200      30000       2016-01-02
  Google    500      50000       2016-01-03

Hire_Table 的布局如下所示：

 site      Hiredate
 Yahoo    2016-03-01
 Yahoo    2016-04-02
 Yahoo    2016-04-28
 Bing     2016-03-01
 Bing     2014-06-01

我加入了两个表，我的代码列在下面：

 select hire.site, cost.mediaspend,cost.impression,count(hire.site) as hires from Hire_Table Hire

 Full Join

(select sitename, sum(cost) as mediaspend, sum(impressions) as impression from Cost_Table
 where deliverydate between '2016-01-01' and '2016-07-31'
 group by sitename)  cost  

 on hire.site=cost.sitename

 group by hire.site, cost.mediaspend,cost.impression

结果是：

 sitename   mediaspend   impression   hires
  Yahoo       300          30000        3
  Bing        --            --          2

但是，这不会给我网站名称，而不是 Hire_Table ，例如 Google 。我尝试使用 Coalesce ，但它也没有改变结果。的聚结（cost.sitename，hire.site）

我看到一些提到联盟功能的帖子。我认为它可能不适用于我的样本，因为我想从两个表中提取不同的内容。任何灯都将非常感激。谢谢！

Answer 1

SELECT allSites.sitename, costs.mediaspend,  costs.impressions, Hires.hires
FROM (SELECT sitename FROM Cost_Table 
      UNION
      SELECT site     FROM Hire_Table) as allSites
LEFT JOIN (SELECT sitename,                
                  SUM(cost) as mediaspend,
                  SUM(impressions) as impressions
           FROM Cost_Table
           GROUP BY sitename) costs
  ON allSites.sitename = costs.sitename
LEFT JOIN (SELECT site,                
                  COUNT(Hiredate) as hires
           FROM Hire_Table 
           GROUP BY site) Hires
  ON allSites.sitename = Hires.site

在连接时合并两个表中的两列，并使用聚合函数

1 个答案: