Question

如何让playerinit删除emptyseats使用的座位？假设seatid为1，那么它会从seat: 1删除emptyseats吗？

   vm.emptyseats = [
      {seat: 1},
      {seat: 2},
      {seat: 3},
      {seat: 4},
      {seat: 5},
      {seat: 6},
      {seat: 7},
      {seat: 8},
      {seat: 9},
    ];


    vm.playerinit = function(x) {
      console.log("init user data");
      var seatid = x.position;

      // vm.emptyseats remove where seat: seatid

    };

Answer 1

使用原生Array#filter功能：

vm.playerinit = function(x) {
      console.log("init user data");
      var seatid = x.position;

      // vm.emptyseats remove where seat: seatid
      //Using ES6 arrow function syntax
      vm.emptyseats = vm.emptyseats.filter( (empty_seat) => empty_seat.seat !== seatid);
      //Or regular syntax
      vm.emptyseats = vm.emptyseats.filter( function(empty_seat) {     return empty_seat.seat !== seatid});

    };

Answer 2

首先，您需要找到要删除的数组的索引。然后，使用Array.splice()：

var seatid = x.position;
angular.forEach(vm.emptyseats, function(emptyseat, i) {
    if(emptyseat.seat !== seatid) return;
    vm.emptyseats.splice(i, 1);
});

Answer 3

本机JS方法，IE 9 +

vm.emptyseats = vm.emptyseats.filter(function(a) { return a.seat != seatid; });

Array.prototype.filter()

Answer 4

您可以使用简单的for循环删除它：

for(var i = 0; i < emptyseats.length; i++) {
    if(vm.emptyseats[i].seat == seatid) vm.emptyseats.splice(i, 1);
}

使用完整代码：

vm.playerinit = function(x) {
  console.log("init user data");
  var seatid = x.position;

  // vm.emptyseats remove where seat: seatid
  for(var i = 0; i < emptyseats.length; i++) {
      if(vm.emptyseats[i].seat == seatid) {
          vm.emptyseats.splice(i, 1);
          console.log(seatid + " removed!");
      }
  }
};

Answer 5

尝试使用.splice()执行此操作。 vm.emptyseats.splice(0,1);

Angularjs从数组中删除项目的方法

5 个答案: