Question

每次我运行程序并输入一个堆积和圈数时，我得到一个＆＃34; TypeError：piles [pileChoice]未定义＆＃34;错误。我已经尝试过几次调试但是我仍然无法让它正常运行。

var piles = [
  {name: 'Pile A', circles: 'ooooo'},
  {name: 'Pile B', circles: 'ooooo'},
  {name: 'Pile C', circles: 'ooooo'}
];

function boardPrint(){
  console.log("NIM");
  for(var i = 0; i < piles.length; i++) {
    console.log(piles[i].name + ": " + piles[i].circles);
  }
}

function getUserInput(){
  return prompt("Enter the letter for the pile (A-C) and the number of stones you want to remove (1-5). Example: A3").toLowerCase();
}

function userMove(){
  var pileIdx = 0;
  var valid = false;
  var numToRemove = 0;

  while(!valid) {
    var gameIns = getUserInput(); // This will now get called multiple times until user enters valid input
    var pileChoice = gameIns[0]; // This makes 'A' turn into 'a', which makes further logic easier.

    // I rebuilt this part of the function to be a bit cleaner and to show you how switch statements could be used
    switch(pileChoice){
      case 'a':
      pileIdx = 0;
      valid = true;
      break;
      case 'b':
      pileIdx = 1;
      valid = true;
      break;
      case 'c':
      pileIdx = 2;
      valid = true;
      break;
      default:
      alert('Error! Invalid input.');
    }
    numToRemove = Math.min(gameIns[1],piles[pileChoice].circles.length); // This way, they can't select a number that is greater than the number remaining in the pile.
  }

  piles[pileIdx].circles = piles[pileIdx].circles.slice(numToRemove);
}

function computerMove(move){
  // Task 1: pick a pile

  var pileIdx = 0;

  if(piles[0].circles.length > 0) { // tests for whether there are circles left in pile A
    piles[0].circles = piles[0].circles.slice(pileIdx);  // do something

  } else if(piles[1].circles.length > 0) {
    piles[1].circles = piles[1].circles.slice(pileIdx);  // do something

  } else if(piles[2].circles.length > 0) {
    piles[2].circles = piles[2].circles.slice(pileIdx);  // do something
  }

  // Task 2: pick a number to remove from the pile

  // Optional: see how many piles are left and base your number to remove on that
  //var pilesCount = 0;

  // [some logic for counting piles]

  // Otherwise, just remove all that are remaining from a pile
  //var numToRemove = 0;

  if (pilesCount > 1){
    // select a number to remove
  }
  else {
    // select another number to remove
  }

  piles[pileIdx].circles = piles[pileIdx].circles.slice(numToRemove);
}

while(true) {
  boardPrint();
  userMove();

  if (boardEmpty() === true) {
    boardPrint();
    console.log("You win!");
    break;
  }

  boardPrint();
  computerMove();

  if (boardEmpty() === true) {
    boardPrint();
    console.log("Computer wins!");
    break;
  }
}

function boardEmpty() {
  // Check if the board is empty
}

Answer 1

在userMove函数中，在while循环结束时，您尝试使用以下行设置numToRemove：

numToRemove = Math.min(gameIns[1],piles[pileChoice].circles.length); // This way, they can't select a number that is greater than the number remaining in the pile.

但是pileschoice要么是'a'，'b'还是'c'，对吧？这就是你在交换机中计算pileIdx的原因。您需要使用它，因为您定义桩的方式不能用'a'，'b'或'c'索引。

Answer 2

我认为问题在于：

你有

var piles = [
  {name: 'Pile A', circles: 'ooooo'},
  {name: 'Pile B', circles: 'ooooo'},
  {name: 'Pile C', circles: 'ooooo'}
];

然后再

numToRemove = Math.min(gameIns[1],piles[pileChoice].circles.length);

我认为你的意思是piles[pileIdx]？ pileChoice将成为一个字母，并且您有一个对象数组，因此您需要使用索引访问正确的对象。

Answer 3

你试图在gameIns [0]中引用piles[pileChoice]像piles ['a']，piles ['b']等等，但是piles数组没有以这种方式格式化，因为桩是一个对象数组。

您可以尝试重新考虑您对桩的建模方式，或尝试使用以下方法获取circle.length：

// define pileCircleCount
var pileCircleCount;

// go over your piles array
piles.forEach(function(pile) {

 // get the pile name value and retrieve the last char which is A/B/C
 // and convert it to lowercase
 var pileId = pile.name.substr(pile.name.length - 1).toLowerCase();

 // now match it up with the pileChoice, if a match is found get its
 // circle length and set it to the pileCircleCount
 if(pileId === pileChoice) {
   pileCircleCount = pile.circles.length;
 }
});

numToRemove = Math.min(gameIns[1], pileCircleCount);

我在执行此javascript程序时遇到问题

3 个答案: