Question

我已经在我编写的数字猜谜游戏中运行了这个代码，如果玩家遵循指示，它运行得非常好，但我们都知道用户永远不会这样做。如果用户只输入一个空格或任何不是单词提示的字符串，那么当它尝试将guess的值转换为整数时，它会崩溃说int（）的无效文字。有什么方法可以解决这个问题，还是我只能和崩溃一起生活？

while repeat==1:
    repeat=0
    level1number=str(level1number)
    guess=input("What is your guess? ")
    guess=guess.lower()
    if guess==level1number:
        print("Well done, You have guessed my number!")
    elif guess=="hint":
        print("Hints are not available until level 3")
        repeat=1
    elif guess!=level1number:
        print("Sorry that is not my number, you have lost a life. :(")
        lives=lives-1
        repeat=1
        if lives<=0:
            print("You have lost all your lives, so this means I win")
            print("The program will now end")
            exit()
            input("")
        level1number=int(level1number)
        guess=int(guess)
        if guess<level1number:
            print("The target number is higher")
        else:
            print("The target number is lower")

Answer 1

使用某些内容

if guess.isdigit() ...

（当且仅当给定字符串的所有字符都是数字时，方法isdigit()才返回true，即0到9）

Answer 2

while repeat==1:
    repeat=0
    level1number=str(level1number)
    guess=input("What is your guess? ")
    guess=guess.lower()
    if guess==level1number:
        print("Well done, You have guessed my number!")
    elif guess=="hint":
        print("Hints are not available until level 3")
        repeat=1
    elif guess!=level1number:
        print("Sorry that is not my number, you have lost a life. :(")
        lives=lives-1
        repeat=1
        if lives<=0:
            print("You have lost all your lives, so this means I win")
            print("The program will now end")
            exit()
            input("")
        level1number=int(level1number)
        try:
            guess=int(guess)
            if guess<level1number:
                print("The target number is higher")
            else:
                print("The target number is lower")
        except:
            print("Try again. Not a number")

使用try/except块可以解决您的问题。看看

编辑：在问题中。你提到当输入数字以外的东西时你会收到错误。实际上，当你的代码试图将输入字符串转换为数字时，由于输入不是数字而导致输入字符串转换为数字时，会抛出exception，就像{guess = int(guess) {1}}。所以，我的代码所做的是，它捕获异常，并且不允许程序以异常终止。

试试一次。我知道你是初学者，但在编写越来越复杂的代码和应用程序之前，最好尽快了解space。

希望它有所帮助!!

将字符串转换为int会导致程序崩溃

2 个答案: