Question

我有两个数字数组说：

$x = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16);
and
$y = array(1,3,6);

如何计算它们之间的差异。我喜欢这样的结果：

$result = array(2,4,5,7,8,9,10,11,12,13,14,15,16);

即数字数组返回类型，我使用了array_diff()和array_assoc_diff() 但我得到一个字符串数组

谢谢

Answer 1

哦，坦克家伙，我修复了问题，在我的代码中某处出现了错误

这实际上是代码：

<?php
    $schedule_id = $_POST['schedule_id'];;
    $query = " SELECT seat_selected FROM masstransit_reserve WHERE schedule_id = '".$schedule_id."' ";
    $result = mysqli_query($dbConn,$query) or die("Error: ".mysqli_error($dbConn));

    $occupied_seats = array();
    foreach($result as $row){
        $occupied_seats[] = $row;
    }

    $seats = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16);



    $result1 = array_diff($seats, $occupied_seats);




    echo json_encode($result1);
?>

因为这行中的[] $ occupied_seats [] = $ row; 我收到了错误。我刚删除它并且效果很好

Answer 2

您也可以使用此代码：

$x = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16);

$y = array(1,3,6);

$z = array();
foreach ($x as $value) {
   if(!in_array($value, $y)) {
        $z[] = $value;
    }
}
print_r($z);

php中两个数值数组的区别

2 个答案: