Question

我有一个目录，用户上传的所有歌曲都会上传。我已经使用mongodb这个应用程序，mongodb工作正常，但我想使用 src url like uploads / something to songs / user / songname我试过使用Router.get，如Controller.js所示但是当我使用它时，我有内部500错误，请让我知道我犯了错误。

controller.js

Router.get('/songs/:artist/:song', (req, response) => {
    console.dir(req.query)
    let file = './uploads/01-Whole Lotta Love.mp3'
    var stat = FileSystem.statSync(file)

    response.setHeader('Content-Type', 'audio/mpeg');
    response.setHeader('Content-Length', stat.length);

    fs.createReadStream(file).pipe(response);
})

app.js

app.use(Express.static(path.join(__dirname, 'uploads')));

profile.ejs

<table border="1">
    <% artist.songs.forEach((song) => { %>
    <tr>
        <td> <%= song.song %> </td>
        <td>
            <audio controls>
                <source src="./songs/<%= artist.artistName+ '/' + song.audioPath %>" type="audio/mpeg">
                Your browser does not support the audio element.
            </audio>
        </td>
        <td>3k listens</td>
        <td>2k likes</td>
        <td>2k comments</td>
    </tr>
    <% }) %>
</table>

就像我为 songs / anyusername / songname 所写的那样，将使用目录上传/歌曲名称

提前谢谢你：）

Answer 1

尝试使用此代码，在浏览器中打开：http://host:port/song/foo/bar
并在评论中写下你得到的：

const 
  fs = require('fs'),
  path = require('path'),
  bufferSize = 100 * 1024;

Router.get('/songs/:artist/:song', (req, res) => {
  let 
    file = '01-Whole Lotta Love.mp3';
    file = path.join(__dirname, 'uploads', file);

  console.log('Piping file:', file); // check if path is correct

  fs.stat(file, 
    (err, stat) => { 
      if(err) {
        return res.status(500).send(err); // output error to client
      }

      res.writeHead(200, {
        'Cache-Control': 'no-cache, no-store, must-revalidate',
        'Pragma': 'no-cache',
        'Expires': 0,
        'Content-Type': 'audio/mpeg',
        'Content-Length': stat.size
      });
      fs.createReadStream(file, {bufferSize}).pipe(res);
  });
})

将静态URL更改为Dynamic - NodeJS

1 个答案: