我有这个类用于存储工具的首选项。该类使用toString()将自身转换为JSON。当我将对象转换为JSON时,我收到此无限递归错误,我无法弄清楚原因。我没有任何循环引用,所以它让我有点困惑。任何帮助将不胜感激。
这是我的班级结构:
public class ToolPrefs
{
private boolean isFloating;
private ToolPalettePlacement placement; //this is an enum
private boolean isSelected;
private int dockLocation;
private Point dialogLocation;
private Dimension dialogSize;
public ToolPrefs(){}
public boolean isFloating(){return isFloating; }
public void setFloating(boolean floating){ isFloating = floating; }
public ToolPalettePlacement getPlacement(){ return placement; }
public void setPlacement(ToolPalettePlacement placement){ this.placement = placement;}
public boolean isSelected(){ return isSelected;}
public void setSelected(boolean selected){isSelected = selected;}
public int getDockLocation(){return dockLocation;}
public void setDockLocation(int dockLocation){this.dockLocation = dockLocation; }
public Point getDialogLocation(){return dialogLocation;}
public void setDialogLocation(Point dialogLocation){ this.dialogLocation = dialogLocation;}
public Dimension getDialogSize(){ return dialogSize; }
public void setDialogSize(Dimension dialogSize){this.dialogSize = dialogSize;}
@JsonIgnore @Override
public String toString()
{
String json;
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
try
{
json = ow.writeValueAsString(this);
}
catch (IOException e)
{
e.printStackTrace();
json = "";
}
return json;
}
}
以下是我收到的异常代码段:
com.fasterxml.jackson.databind.JsonMappingException:无限递归(StackOverflowError)(通过引用链:java.awt.Point [" location"] - > java.awt.Point [&#34 ;位置"] - > java.awt.Point中["位置"] - > java.awt.Point中["位置"] ...) 在com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:518) 在com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:117) at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:464) 在com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:504) 在com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:117) at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:464) 在com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:504) 在com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:117) at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:464) 在com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:504) 在com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:117)
答案 0 :(得分:3)
您遇到的问题是由于您的对象正在嵌入的Point
类。
要解决此问题,您可以指示Jackson停留在第一级深度,并且要实施此解决方案,您可以按照以下步骤操作:
1)首先,你必须运行杰克逊的2.x版本,我用这个测试了解决方案:
<dependencies>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.8.3</version>
</dependency>
</dependencies>
2)初始化ObjectMapper
的新实例时,请执行以下操作:
ObjectWriter ow = new ObjectMapper().configure(DEFAULT_VIEW_INCLUSION, true).writer().withDefaultPrettyPrinter();
3)如果您拥有Point
类型,请使用注释:
@JsonView(Point.class) Point dialogLocation;
杰克逊将停在第一级,结果将是:
{
"dialogLocation" : {
"x" : 2.0,
"y" : 3.0
}
}
有关进一步的文档,您可以看到:
Limit Jackson output to only one level
Enable default view inclusion on Jackson 2.x ObjectMapper
我已经测试了解决方案,只要您使用2.x版本的Jackson,它就能正常运行。使用1.x,我无法让它运行起来。
答案 1 :(得分:-2)
或试试这个
ObjectMapper mapper = new ObjectMapper();
String perttyStr = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(object);