Question

我想从列column1中获取值并删除所有值 （空格，％20，％2520，_（下划线）， - （连字符）和。（点））并将值保存到其他column2中的相应位置。<登记/> 这是正确的方法吗？这会工作吗？

$conn = new mysqli($servername, $username, $password,$dbname);

$sql= "SELECT column1 FROM table" ;

$result = $conn->query($sql);

if ($result->num_rows > 0) {

while($row = $result->fetch_assoc()) {


    $x= $row["column1"] ;


$find=array(" ","%20","%2520",".","-","_");
$x= str_replace($find,'',$x);


               $sql2 ="INSERT INTO table
             ( column2 )
             VALUES
             ( '$x' )";

              if ($conn->query($sql2) === TRUE) {
               echo "Record Created <br>";

                }

              else {
               echo "Error creating Record: " . $conn->error;
               }

    }
} else {
    echo "0 results";
}
$conn->close();

Answer 1

您需要Update而不是Insert。

使用REPLACE功能删除列中不需要的字符

首先运行select并检查一切是否正常，然后运行update

SELECT column1,
       Replace(Replace(Replace(Replace(Replace(Replace(column1, ' ', ''), '%2520', ''), '%20', ''), '_', ''), '-', ''), '.', '') AS column2
FROM   yourtable 

UPDATE tablename
SET    column2 = Replace(Replace(Replace(Replace(Replace(Replace(column1, ' ', ''), '%2520', ''), '%20', ''), '_', ''), '-', ''), '.', '')

Answer 2

First Step

UPDATE table SET column1 = column2

Second Step

UPDATE table SET column2 = REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(column2, ' ', '') , '%20', '') ,'%2520', ''), '.', '') , '-', '') , '_', '')

php，sql - 如何改变一列的值并将其插入其他列

2 个答案: