将daterangepicker文本转换为datetime输入

时间:2016-10-15 13:10:09

标签: javascript datetime cakephp-3.0 daterangepicker

我试图将DateRangePicker使用的文本输入转换为日期时间输入,因为我的所有日​​期都是日期时间格式。我的代码如下:

<!-- Include Required Prerequisites -->
<script type="text/javascript" src="//cdn.jsdelivr.net/jquery/1/jquery.min.js"></script>
<script type="text/javascript" src="//cdn.jsdelivr.net/momentjs/latest/moment.min.js"></script>
<link rel="stylesheet" type="text/css" href="//cdn.jsdelivr.net/bootstrap/latest/css/bootstrap.css" />

<!-- Include Date Range Picker -->
<script type="text/javascript" src="//cdn.jsdelivr.net/bootstrap.daterangepicker/2/daterangepicker.js"></script>
<link rel="stylesheet" type="text/css" href="//cdn.jsdelivr.net/bootstrap.daterangepicker/2/daterangepicker.css" />

<script type="text/javascript">
  $(function() {
    $('input[name="date_start"]').daterangepicker({
        autoUpdateInput: false,
        locale: {
            cancelLabel: 'Clear'
        },
        format: "DD/MM/YYYY",
        startDate: new Date(new Date().getTime() + 24 * 60 * 60 * 1000),
        endDate: new Date(new Date().getTime() + 24 * 60 * 60 * 1000),
        minDate: new Date(new Date().getTime() + 24 * 60 * 60 * 1000)
    });

    $('input[name="date_start"]').on('apply.daterangepicker', function(ev, picker) {
        $(this).val(picker.startDate.format('DD/MM/YYYY') + ' - ' + picker.endDate.format('DD/MM/YYYY'));
        $("#date_start").val(picker.startDate.format('DD/MM/YYYY'));
        $("#date_end").val(picker.endDate.format('DD/MM/YYYY'));
    });

    $('input[name="date_start"]').on('cancel.daterangepicker', function(ev, picker) {
        $(this).val('');
    });
  });
</script>

<div class="container" style="margin-top: 70px;">
    <?= $this->Flash->render('auth') ?>
    <?php $this->Form->templates([
        'inputContainer' => '<div class="form-group">{{content}}</div>',
        'inputContainerError' => '<div class="error" style="color:red;">{{content}}{{error}}</div>'
    ]);?>
    <div class="col-sm-2">
    </div>
    <div class="col-sm-8">
        <div class="container col-sm-12" style="border-radius: 10px; border: 1px solid;" >
            <?= $this->Form->create() ?>

            <div class="col-sm-6">
                <?= $this->Form->input('date_start', ['class'=>'form-control', 'type'=>'text', 'label'=>'Session Dates',
                'placeholder'=>'Please select the start and end dates for your session.']);?>
            </div>

            <input type="text" name="date_start" id="date_start" value="" />
            <input type="text" name="date_end" id="date_end" value="" />

                        <input id='date_start' class='form_control' name='date_start'/>
            <input id='date_end' class='form_control' name='date_end'/>

            <script>
                <?php $date_starttext ?> = document.getElementById('date_start').value;
                <?php $date_endtext ?> = document.getElementById('date_end').value;
                <?php $date_startdt = DateTime::createFromFormat('d/M/Y', $date_starttext)->format('Y-M-d'); ?>
                <?php $date_enddt = DateTime::createFromFormat('d/M/Y', $date_endtext)->format('Y-M-d'); ?>
            </script>

            <div>
            <?= $this->Form->input('sessions.0.date_start', ['class'=>'form-control', 'type'=>'hidden', 'value'=>$date_startdt]); ?>
            </div>
            <div>
            <?= $this->Form->input('sessions.0.date_end', ['class'=>'form-control', 'type'=>'hidden', 'value'=>$date_enddt]);?>
            </div>

            <input type="text" name="sessions.0.date_start" id="sessions.0.date_start" value="" />
            <input type="text" name="date_start5" id="sessions.0.date_start" value="" />
            <input type="text" name="sessions.0.date_end" id="date_end5" value="" />

            <?= $this->Form->end() ?>
          </div>
          </div>
          <div class="col-sm-2">
          </div>
          </div>

但是,当我尝试使用此代码加载页面时,我收到此错误:

  

在布尔值

上调用成员函数format()

错误消息引用此行:

<?php $date_startdt = DateTime::createFromFormat('d/M/Y', '$date_starttext')->format('Y-M-d'); ?>

我不完全确定错误。据推测,DateTime:createFromFormat下面也有同样的错误。

1 个答案:

答案 0 :(得分:0)

根据文档,DateTime :: createFromFormat方法在失败时返回一个新的DateTime实例或FALSE,所以我猜你正在传递一个无效的字符串进行解析,并且该方法返回boolean值为false。