你知道oracle中的函数或过程,它将允许我:
TABLE Clients
COLUMN id, name, vlag
columnname column_value
id 1
name Jon
flag M
columnname column_value
id 2
name Jessica
flag F
答案 0 :(得分:2)
with dat as (select '1' as id, 'Jon' as name, 'M' as vlag from dual union all
select '2' as id, 'Jessica' as name, 'F' as vlag from dual)
select * from dat unpivot (column_value for column_name in (id, name, vlag));
但结果将与之前的答案非常相似(如果你添加rownum并用作键)。
答案 1 :(得分:0)
试试这个。但我会说这是无效的
select 'id' as column_name, id as column_value from table
union all
select 'name',name from table
union all
select 'flag',vlag from table