Question

我做的是：

在Windows上

，按“Windows”按钮，弹出开始菜单。我开始打字：

"C:\Windows\System32\cmd.exe" /k "C:\Program Files (x86)\my\my.exe" -c "C:\Program Files (x86)\my\data.conf" -cert "C:\Program Files (x86)\my\my.key"

但是当cmd提示出现时，它会显示：

'C:\Program' is not recognized as an internal or external command,
operable program or batch file.

不确定为什么这会给我错误，因为我已经在路径周围引用了。这可能只是一些愚蠢的事情，但非常感谢第二双眼睛！

Answer 1

使用cmd /?

中的以下说明

否则，旧行为是查看第一个字符是否为引号字符，如果是，则删除前导字符并删除最后一个字符   在命令行上引用字符，保留后面的任何文本   最后引用字符。

您的行应更正为：

"C:\Windows\System32\cmd.exe" /k ""C:\Program Files (x86)\my\my.exe" -c "C:\Program Files (x86)\my\data.conf" -cert "C:\Program Files (x86)\my\my.key""

（基本上是"cmd.exe" /k "command using "quoted parts""（在引用的表达式中引用了字符串）

注意：您也可以（应该）使用"C:\Windows\System32\cmd.exe"

代替"%comspec%"

Answer 2

当一行只有两个时，双引号字符只能由cmd正确处理。删除所有内容，包括＆＃34; / k＆＃34;从你输入的内容和运行结果 - 它在类似的情况下对我有用。请注意，您可以将键入的内容保存到.bat文件中，然后运行该文件以保存重复键入（或重复粘贴）。

证据可以在http://www.computerhope.com/cmd.htm找到，或者如果你运行：

cmd /?

您将看到以下内容：

If /C or /K is specified, then the remainder of the command line after the
switch is processed as a command line, where the following logic is used to
process quote (") characters:

1. If all of the following conditions are met, then quote characters on 
the command line are preserved:    
 - no /S switch
 - exactly two quote characters
 - no special characters between the two quote characters, where special is
   one of: &<>()@^|
 - there are one or more whitespace characters between the two quote
   characters
 - the string between the two quote characters is the name of an executable
   file.

2. Otherwise, old behavior is to see if the first character is a quote
character and if so, strip the leading character and remove the last quote
character on the command line, preserving any text after the last quote
character.

为什么cmd会抛出C：\ Program甚至在路径周围都有引号？

2 个答案: