Question

嗨我想分开以下 - 和;和：在sql server中插入另一个表

declare @data varchar(max)=null
set @data='nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'


col1     col2           col3     col4
Nt  895067021846160     2       7.5.05
nt  875067021846160     3      8.5.05
nt  835067021846160     5      8.5.05

等等

我使用了substring和CHARINDEX但是我没有得到正确的结果。感谢

Answer 1

有许多解决方案可用于字符串拆分要求，您可以使用此处的字符串夹板功能fnSplitString

我只是在你的案例中演示了如何使用这个功能。

尝试使用-

转换所有;，:

declare @data varchar(max)=null
set @data='nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'
SET @data=REPLACE(REPLACE(@data,'-',':'),';',':')

现在调用此fnSplitString，如下所示，这将为单列表提供所有字符串片段。

INSERT INTO #TableName(Col1) SELECT * FROM dbo.fnSplitString(@data,':')

这将给出这样的OUTPUT

nt
865067021846160
2
8.5.05
1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11
101
100
0
0
0
FF
146
25}

Answer 2

尝试使用以下脚本。

DECLARE @data VARCHAR(Max) = 'nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'
DECLARE @SpitChars varchar(100) = '%[:;-]%'

;WITH cte_1 
  AS
    (
        SELECT PATINDEX(@SpitChars, @data) - 1 + case when  PATINDEX(@SpitChars, Left(@data,1)) = 1 then 1 else 0 end AS LineBreaker
            , @data AS dataString
            ,SUBSTRING(@data, 1, ISNULL(NULLIF(PATINDEX(@SpitChars, @data), 0) - 1 +case when  PATINDEX(@SpitChars, Left(@data,1)) = 1 then 1 else 0 end, 8000)) AS [Extract]
        UNION ALL
        SELECT LineBreaker + ISNULL(NULLIF(PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)), 0) -  case when  PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)) = 1 then 0 else 1 end  ,datalength(dataString)-LineBreaker) LineBreaker
            , dataString
            ,SUBSTRING(dataString, LineBreaker+ 1 , ISNULL(NULLIF(PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)), 0) -  case when  PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)) = 1 then 0 else 1 end  ,datalength(dataString)-LineBreaker)) AS [Extract]
        FROM  cte_1
        WHERE LineBreaker BETWEEN 1 AND datalength(@data)-1 
    )
SELECT [1] Col1,[2] Col2,[3] Col3,[4] Col4,[5] Col5
      ,[6] Col6,[7] Col7,[8] Col8,[9] Col9,[10] Col10
      ,[11] Col11,[12] Col12,[13] Col13
FROM(
SELECT [Extract],ROW_NUMBER()OVER( ORDER BY (SELECT 1))RNO
FROM  cte_1
WHERE [Extract] NOT IN (':',';','-'))t
PIVOT(MAX([Extract]) FOR [RNO] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13]) )as pvt

在sql中拆分字符串并将每个seprareted值添加到表的每一列中

2 个答案: