我是Redux模式的新手,我在将单独的JS文件中的操作链接到它的父组件时遇到了一些麻烦。这是组件:
import React, {Component} from 'react';
import {bindActionCreators} from 'redux';
import {connect} from 'react-redux';
import playSample from './sampleActions/clickToPlay';
class SamplesInnerLrg extends Component {
render() {
return <div>
{
this.props.samples.map((sample) => {
return (
<div key={sample.id} className="sample-comp-lge">
<div className="sample-comp-lge-header">
<span className="sample-comp-lge-Name">{sample.sampleName}</span>
<span className="sample-comp-lge-id">{sample.sampleFamily}</span>
</div>
<div className="sample-comp-lge-audio" ref={sample.id} onClick={() => this.bind.playSample(sample)}>
<audio preload="auto" id="myAudio">
<source src={sample.soundSource} type="audio/wav" />
</audio>
</div>
<div className="sample-comp-lge-owner">{sample.uploader}</div>
</div>
)
})
}
</div>
}
}
function mapStateToProps(state) {
return {
samples:state.samples
};
}
function matchDispatchToProps(dispatch) {
return bindActionCreators({playSample:playSample},dispatch)
}
export default connect(mapStateToProps,matchDispatchToProps)(SamplesInnerLrg);
具体来说,我试图对此行进行onClick操作,该操作将调用导入文件中的函数(clickToPlay.js):
<div className="sample-comp-lge-audio" ref={sample.id} onClick={() => this.bind.playSample(sample)}>
clickToPlay文件如下所示:
import $ from 'jquery';
export const playSample = (sample) => {
console.log(sample);
return {
type:"Play_Sample_clicked",
payload:sample
}
};
我点击的错误是无法阅读属性&#39; playSample&#39;未定义的。我猜测我已经将操作严格限制在组件中,但我不知道为什么?
编辑:
这是我索取的index.js文件:
import React from 'react';
import ReactDOM from 'react-dom';
import App from './App';
import {Provider} from 'react-redux';
import { createStore,compose } from 'redux';
import allReducers from './reducers';
const store = createStore(allReducers,compose(
window.devToolsExtension ? window.devToolsExtension() : f => f
));
ReactDOM.render(
<Provider store={store}>
<App />
</Provider>
,
document.getElementById('root')
);
答案 0 :(得分:0)
您没有将'playSample'导出为默认导出,您有两种方法可以重新开发:
你可以这样做:
import { playSample } from './sampleActions/clickToPlay';
或
您可以将export const playSample
更改为const playSample
然后在文件末尾添加export default playSample
。
我想提及另一个关于这一行的说明:
return bindActionCreators({playSample:playSample},dispatch)
我不明白您为什么要{playSample:playSample}
将其更改为playSample
。如果密钥与值相同,ES6允许您删除密钥,这称为对象文字属性值缩写。