Question

在我的Django模板中，我有一个从QuerySet构建的图表，按def cvt(ustring): l = [] for uc in ustring: l.append(chr(ord(uc) & 0xFF)) # low order byte l.append(chr((ord(uc) >> 8) & 0xFF)) # high order byte return ''.join(l) cvt(my_string) 'WAGCenter-04190517953516060503-20160605124857-4190-5'递减排序，类似这样（省略任何HTML标记）：

score

但是，如果相邻的球员得分相等，我希望他们的位置相同，即：

{% for player in players %}
    {{ forloop.counter }}. {{ player.name }} ({{ player.score }})
{% endfor %}

我是否认为使用Django的标准模板标签（我不使用Jinja）无法做到这一点？最好的方法是在视图中（或者它来自何处）遍历QuerySet并在那里计算这些位置，在它们到达模板之前将它们添加到每个项目中？

Answer 1

这似乎更像是在视图中处理的事情：

players = your_queryset
ordered_players = []
counter = 1
previous_player = PlayerModel.objects.none()
for player in players.order_by("score"):
  if player.score == previous_player.score:
    position = previous_player.position
  else:
    position = counter
  ordered_players.append({
    "position": position, 
    "name": player.name,
    "score": player.score
  })
  previous_player = player
  counter += 1
return render(request, "template.html", {"players": ordered_players})

模板：

{% for player in players %}
    {{ player.position }}. {{ player.name }} ({{ player.score }})
{% endfor %}

Django模板中具有相同位置的编号列表？

1 个答案: