Question

我似乎在这个购物车中找不到任何错误，但它显示不正确..我看过这个YouTube视频，并从那里尝试了代码（https://www.youtube.com/watch?v=SlwMBtx0YMQ），但它改为使用MySQL MYSQL PDO;所以我转而使用PDO。我从另一个页面回显该类以显示HTML代码。是的，我是新来的..

代码从挪威语翻译成英语：

<?php
    class shoppingCart {
        // This function works as it should it seems like
        function writeShoppingCart() {
            $cart = $_SESSION["cart"];
            if (!$cart) {
                return "0 products";
            } else {
                $products = explode(",",$cart);
                $number = (count($products) > 1) ? "s" : "";
                return "<a href='cart.php'>".count($products)." Products ".$number."";
            }
        }
        // But this function is not working as it should (?)
        function showCart() {
            $cart = $_SESSION["cart"];
            if ($cart) {
                $products = explode(",",$cart);
                $content = array();
                // FAULT HERE MAYBE ?
                foreach ($products as $product) {
                    $content[$product] = (isset($content[$product])) ? $content[$product]+1 : 1;
                }
                $output[] = '<form action="cart.php?action=update" method="POST" id="cart"';
                $output[] = '<table>'; // This was corrected by "jeyoung" (">")
                // HERE ? $content .. I THINK
                foreach ($content as $productID=>$qty) {
                    $sql = "SELECT * FROM Product WHERE ProductID = ".productID;
                    // FAULT HERE ....?
                    echo " WORKS HERE 1 "; // From here and down the code stops displaying ...
                    $result = $conn->query($sql);
                    echo " WORKS HERE 2 "; // This is just check-marks to make it easier to find the fault ..
                    $user_data = $result->fetch(PDO::FETCH_BOTH);
                    echo " WORKS HERE 3 ";
                    extract($user_data);

                    $output[] = '<tr>';
                    $output[] = '<td><a href="cart.php?action=delete&id='.$productID.'" > Delete </a></td>';
                    $output[] = '<td>'.$productName.'</td>';
                    $output[] = '<td>NOK '.$PriceNOK.',-</td>';
                    $output[] = '<td><input type="text" name="qty'.$productID.'" value='.$qty.' size="3" maxlength="3" /></td>';
                    $output[] = '<td> NOK '.($PriceNOK * $qty).',-</td>';
                    $totalCost += $PriceNOK * $qty;
                    $output[] = '</tr>';
                    echo " WORKS HERE 4 ";
                }
                $output[] = '</table>';
                $output[] = '<p> Total: <strong>NOK '.$totalCost.',-</strong></p>'; // NOK = Norwegian Kroner (currency)
                $output[] = '<button type="submit">Update Cart</button>';
                $output[] = '</form>';
            } else {
                $output[] = '<p>Cart is empty.</p>'; // Cart empty
        }
            return join('',$output);
        }
    }
    ?>

Answer 1

在此行$produksjon[] = '<table';上，代码未正确关闭。

应为$produksjon[] = '<table>';。

Answer 2

您的功能出错

    function showCart() {
        $cart = $_SESSION["cart"];
        if ($cart) {
            $output = explode(",",$cart);
            $content = array();
            // FAULT HERE MAYBE ?
            foreach ($products as $product) {

您的foreach已使用$products，但您没有此变量。您需要像在第一个函数中那样分配该变量。而不是

$output = explode(",",$cart);

使用

$products = explode(",",$cart);

代码开头的“s”不是拼写错误，如果需要，它应该将产品变成产品。

Answer 3

我忘了在ShoppingCart类中定义$ conn。我只在外面定义了它！不知道这是必要的。

无法让OOP正常工作 - 购物车，PHP

3 个答案: