输出

Question

我会尽量保持简短。这是我的任务（太大了，无法复制）：

[练习图片1] [2] [练习图片2] [1]

这么长的故事，我已经创建了一个新的数据样式，它将包含3个值（a，b和c），这些必须放入一个等式中，然后它将计算根并显示它。我还没有完成，但我在排序值时遇到了一些问题（我们必须这样做）

Answer 1

根据我的评论：

我相信如果你将pass初始化为0，将i初始化为（pass + 1），用V [pass]替换所有V [i]，用V [i]替换所有V [i + 1]，你的代码应该按预期工作

void swap(Quadratic_equation arr[], int lowerIndex, int higherIndex) {
    Quadratic_equation temp = arr[lowerIndex];
    arr[lowerIndex] = arr[higherIndex];
    arr[higherIndex] = temp;
}
void sort_equation_array(Quadratic_equation V[], int howMany)
{
     for ( int pass = 0; pass < howMany; pass++ )
       {                   

         for (int i = (pass + 1); i <= howMany -1; i++)     
         {
             if (V[pass].a > V[i].a)
             {
                 swap(V, pass, i);
             }
             else if (V[pass].a == V[i].a &&
                      V[pass].b > V[i].b)
             {
                 swap(V, pass, i);
             }
             else if (V[pass].a == V[i].a &&
                 V[pass].b == V[i].b &&
                 V[pass].c > V[i].c)
             {
                 swap(V, pass, i);
             }
         }
      }
}

您还应该清理输入，以便更容易分辨哪些值在哪里。这就是我所做的，你可以改变它来说出你喜欢的，但你明白了。

void get_quadratic_equation(Quadratic_equation &e)
{
    cout << "a: ";
    cin >> e.a;
    cout << "b: ";
    cin >> e.b;
    cout << "c: ";
    cin >> e.c;
}

int load_equation(Quadratic_equation V[], int n)
{
     Quadratic_equation e;

     int counter = 0; 
     cout << endl << "Set values for equation " << counter << endl;
     get_quadratic_equation(e); 

     while (e.a != 0)
     {
         V[counter] = e; 
         ++counter;

         if (counter == n) break;
         cout << endl << "Set values for equation " << counter << endl;
         get_quadratic_equation(e); 
     }
     cout << endl;
     return counter;
}

输出

** Enter Quadratic Equations **

Set values for equation 0
a: 1
b: 2
c: 3

Set values for equation 1
a: 4
b: 5
c: 6

Set values for equation 2
a: 7
b: 8
c: 9

Set values for equation 3
a: 8
b: 7
c: 6

Set values for equation 4
a: 5
b: 4
c: 3

Set values for equation 5
a: 2
b: 1
c: 0

Set values for equation 6
a: 0
b: 0
c: 0

** NOT SORTED **
1x^2 + 2x + 3     root 1 = -1.00+i 1.41       root 2 = -1.00-i 1.41
4x^2 + 5x + 6     root 1 = 0.00+i 1.05       root 2 = 0.00-i 1.05
7x^2 + 8x + 9     root 1 = 0.00+i 0.98       root 2 = 0.00-i 0.98
8x^2 + 7x + 6     root 1 = 0.00+i 0.75       root 2 = 0.00-i 0.75
5x^2 + 4x + 3     root 1 = 0.00+i 0.66       root 2 = 0.00-i 0.66
2x^2 + 1x + 0     root 1 = 0.00       root 2 = -0.50

** SORTED BY A **
1x^2 + 2x + 3     root 1 = -1.00+i 1.41       root 2 = -1.00-i 1.41
2x^2 + 1x + 0     root 1 = 0.00       root 2 = -0.50
4x^2 + 5x + 6     root 1 = 0.00+i 1.05       root 2 = 0.00-i 1.05
5x^2 + 4x + 3     root 1 = 0.00+i 0.66       root 2 = 0.00-i 0.66
7x^2 + 8x + 9     root 1 = 0.00+i 0.98       root 2 = 0.00-i 0.98
8x^2 + 7x + 6     root 1 = 0.00+i 0.75       root 2 = 0.00-i 0.75

不能冒泡这些值

1 个答案:

输出