CREATE TABLE IF NOT EXISTS `order_order_status` (
`id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`order_status_id` int(11) NOT NULL,
`order_id` int(11) NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `order_order_status_order_status_id_index` (`order_status_id`),
KEY `order_order_status_order_id_index` (`order_id`),
KEY `order_order_status_created_at_index` (`created_at`),
KEY `order_order_status_updated_at_index` (`updated_at`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=5 ;
--
-- Dumping data for table `order_order_status`
--
INSERT INTO `order_order_status` (`id`, `order_status_id`, `order_id`, `created_at`, `updated_at`) VALUES
(1, 2, 1, '2016-10-01 01:57:37', '2016-10-01 01:57:37'),
(2, 2, 2, '2016-10-01 01:57:54', '2016-10-01 01:57:54'),
(3, 2, 3, '2016-10-02 02:12:49', '2016-10-02 02:12:49'),
(4, 6, 3, '2016-10-02 02:14:19', '2016-10-02 02:14:19');
我想选择的是:
1, 2, 1, '2016-10-01 01:57:37', '2016-10-01 01:57:37'
2, 2, 2, '2016-10-01 01:57:54', '2016-10-01 01:57:54'
4, 6, 3, '2016-10-02 02:14:19', '2016-10-02 02:14:19'
这是按order_id
分组的order_order_status的最新条目现在出现了问题:
运行
select *, max(created_at) from `order_order_status` group by `order_order_status`.`order_id`
给我回复:
或在prosa
它返回的不是最新的条目,而是返回旧的order_id 3
答案 0 :(得分:2)
MySQL正如预期的那样完全。问题是你的期望。
带有select *
的 group by
没有意义。你想获得最大值,做这样的事情:
select oos.*
from order_order_status
where oos.created_at = (select max(oos2.created_at)
from order_order_status oos2
where oos2.order_id = oos.order_id
);
聚合(group by
)每组产生一行。诸如max()
之类的聚合函数获取列的最大值 - 仅此而已。它只是在一个列上运行。
当您使用select *
时,您有一堆不在group by
中的列,而不是聚合列的参数。 MySQL允许这种语法(不幸的是 - 很少有其他数据库这样做)。 unaggregated列的值是组中不确定行的任意值。
答案 1 :(得分:0)
按order_id desc使用订单可以解决您的问题
select *, max(created_at) from `order_order_status` group by `order_order_status`.`order_id` order by `order_order_status`.`order_id` desc