Question

您好我的个人项目需要一点帮助我有这样的事情：

的资源文件：

something,something,something,something,something,someth ing,result1
something,something,something,something,something,somethi ng,result2
something,something,something,something,something,someth ing,result3

我需要在最后一行之后编写我的变量，在特定行（我的每行有不同的值）

resultFile：

sed -i "$numberOfLine,/,/ s/,/,$actualDeparture/6" $fileName

我用过这个：

something,something,something,something,something,someth ing,result1
something,something,something,something,something,somethi ng,result2result1
something,something,something,something,something,someth ing,result3result2

但结果是： badResultFile：

{{1}}

我不知道为什么我有结果2和结果1在第二行，我真的绝望，因为我不知道如何解决这个问题。

Answer 1

我会使用awk：

awk '{ print $0 "result" NR }' sourceFile

print $0 "result" NR打印每一行，然后打印字符串result，然后打印每行（记录）编号（NR）

示例：

% cat file.txt something,something,something,something,something,something, something,something,something,something,something,something, something,something,something,something,something,something, % awk '{ print $0 "result" NR }' file.txt something,something,something,something,something,something,result1 something,something,something,something,something,something,result2 something,something,something,something,something,something,result3

Answer 2

使用您的地址范围$numberOfLine,/,/，处理从$numberOfLine到包含,的下一行的所有行。

并且您不需要计算,命令中s的数量，只需将$（行尾）替换为您的变量值。

要单独处理每一行，请尝试以下操作：

sed -i "$numberOfLine s/$/$actualDeparture/" "$fileName"

如何在bash中替换文件中的特定行出现

2 个答案: